Alright
for a 45-45-90 triangle, if the legs are x then the hytponuse is x√2
so LM=x√2 is right
NM=x
also, tan=oposite side/adjacent side
so that would be LN/MN or MN/LN=x/x=1
so that would be tan(45)=1
so you want to check the 1st one, 3rd one and 5th one
NM=x
LM=x√2
tan(45°)=1 are the answers
Answer: 8
Step-by-step explanation:
Answer:
Hello,
Answer 52/3
Step-by-step explanation:
using the theorem of the bissector :
176 = a1 * r^4
704 = a1 * r^6
dividing:-
r^2 = 706/174 = 4 so r = +/- 2
a1 = 176 / 2^4 = 176/16 = 11
So 11 is the first term
There are two circles with center A and D. The tangent line touches both point B and C. The given measurements are enough to solve for the missing value and the solution is shown below:
AB=9
BC=26
DC=8
Solve for the measurement of AC which the hypotenuse of legs AB and BC by Pythagorean theorem:
c²=a²+b²
c²=9²+26²
c=AC=27.51
Solve for angle of A
sin A=26/27.51
A=70.93°
Finally, we solve for the length of AD using SOH
sin 70.93°=AD/27.51
AD=26
The answer is 26.
