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3 years ago

Please someone help

Mathematics

1 answer:

FrozenT [24]3 years ago

3 0

How long will she take to what ?

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A quality control specialist for a restaurant chain takes a random sample of size 14 to check the amount of soda served in the 1

Ilya [14]

At 95% confidence interval, true population mean is given by

x+/- 2sd

where x= sample mean and sd = sample standard deviation
True mean of population = 13.50 +/- 2*1.51 = 13.50+/-3.02

Interval: 13.50+3.02, 13.50-3.02 = 16.51, 10.48

7 0

3 years ago

2y)(2y + 8) = ? A. 4xy – 16x – 4y2 – 16y B. 4xy + 16x – 4y2 – 16y C. 4xy – 4y2 D. 4xy + 16x + 4y2 + 16y 8…

Vilka [71]

4y^2 + 16y
You distribute the 2y into the 2y+8

8 0

4 years ago

Help me pls and thank u

Vesnalui [34]

You have to do the math

7 0

3 years ago

Read 2 more answers

I need to know the improper fractions answers for:

zmey [24]

Answer:

Part 1) $x=\frac{15}{2}\ units$

Part 2) $z=\frac{15\sqrt{3}}{2}\ units$

Part 3) $y= \frac{15\sqrt{3}}{4}\ units$

Part 4) $b= \frac{45}{4}\ units$

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

$cos(60^o)=\frac{x}{15}$ ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

$cos(60^o)=\frac{1}{2}$

substitute

$\frac{1}{2}=\frac{x}{15}$

solve for x

$x=\frac{15}{2}\ units$ ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

$15^2=x^2+z^2$

substitute the value of x

$15^2=(\frac{15}{2})^2+z^2$

solve for z

$z^2=15^2-(\frac{15}{2})^2$

$z^2=225-\frac{225}{4}$

$z^2=\frac{675}{4}$

$z=\frac{\sqrt{675}}{2}\ units$

simplify

$z=\frac{15\sqrt{3}}{2}\ units$

step 3

Find the value of y

In the right triangle of the right

$sin(30^o)=\frac{y}{z}$ ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$sin(30^o)=\frac{1}{2}$

$\frac{1}{2}=y:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{1}{2}= \frac{2y}{15\sqrt{3}}$

$y= \frac{15\sqrt{3}}{4}\ units$

step 4

Find the value of b

In the right triangle of the right

$cos(30^o)=\frac{b}{z}$ ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$cos(30^o)=\frac{\sqrt{3}}{2}$

$\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}$

$b= \frac{45}{4}\ units$

7 0

3 years ago

8m-40= -4(5m+3) What value of m makes the equation true?

azamat

M=1
Pls mark brainliest

7 0

3 years ago

Read 2 more answers