Answer:
hold on might have to ask my teacher
Step-by-step explanation:
Answer:
11.7647059 % gain
Step-by-step explanation:
To find the gain, take the new amount and subtract the original amount
9500-8500 = 1000
Divide by the original amount
1000/8500=.117647059
Multiply by 100% to get in percent form
11.7647059 % gain
Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19
Step-by-step explanation:
Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = birth weights of babies
µ = mean weight
σ = standard deviation
From the information given,
µ = 3500 grams
σ = 560 grams
We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as
P(x > 4000) = 1 - P(x ≤ 4000)
For x = 4000,
z = (4000 - 3500)/560 = 0.89
Looking at the normal distribution table, the probability corresponding to the z score is 0.81
P(x > 4000) = 1 - 0.81 = 0.19
Hey there!
4x + 1/2 + 2x - 3
COMBINE the LIKE TERMS
= (4x + 2x) + (1/2 - 3)
TRYING to SIMPLIFY THEM
4x + 2x
= 6x
1/2 - 3
= -5/2
ANSWER
6x + (-5/2)
Therefore, your answer should be: 6x + -5/2
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Answer:
Just use a calcultor...
Step-by-step explanation:
