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Firlakuza [10]
3 years ago
7

Suppose I measure the length and width of a rectangle, and get L = 4 +/- 1 m and W = 10 +/- 2m. What is the uncertainty (not fra

ctional uncertainty!) in the area of the rectangle? (recall A = LW)
Mathematics
1 answer:
Elodia [21]3 years ago
8 0

Answer:

Step-by-step explanation:

fractional uncertainty, to quantify the precision of a measurement for L and W is

ΔL/L = 1/4 = 0.25 = 25%

ΔW/W = 2/10 = 2/5 = 0.4 = 40%

Now the area of triangle A = L*W = 4*10 = 40m^2

The rules for propagation of error state that when two quantities are multiplied, their fractional uncertainties are added:

So,

ΔA/A = ΔL/L + ΔW/W = 0.25+0.4 = 0.65 =65%

Now we can compute uncertainty in the area, which is

ΔA = A * (ΔA/A) = 40*0.65 = 26%

Finally, we can write the area of the rectangle together with its uncertainty:

A = 40m^2 ± 26%

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PLZ HELP ASAP FEATURES OF A CIRLE FROM EXPANDED EQUATION
Lana71 [14]
First we need to convert the given equation to standard form, only then we can find the center and radius of the circle.

x^{2} + y^{2} +18x+14y+105=0 \\  \\ 
 x^{2} +18x+ y^{2}+14y=-105 \\  \\ 
 x^{2} +2(x)(9)+ y^{2}+2(y)(7)=-105 \\  \\ 
x^{2} +2(x)(9)+ 9^{2} + [y^{2}+2(y)(7)+7^{2}]  =-105+9^{2}+7^{2}  \\  \\ 
 (x+9)^{2}+ (y+7)^{2}=25  


The standard equation of circle is:

(x-a)^{2} + (y-b)^{2}= r^{2}

with center (a,b) and radius = r

Comparing our equation to above equation, we can write

Center of circle is (-9, -7) and radius of the given circle is 5 
8 0
3 years ago
A standard deck of cards has 52 cards, 4 of each type (Ace, King, Queen, Jack, 10,...,2). From a well-shuffled deck, you are dea
Wewaii [24]

Answer:

a)%85,5

b)%92,2

Step-by-step explanation:

a) To determine the probability of getting a hand with at least one face, we need to calculate the probability of the hand without any face firstly.

(36/52)*(35/51)*(34/50)*(33/49)*(32/48)=0,145

Then, we need to deduct this value from the probability 1

1-0,145=0,855

The probability of the hand with at least one face is %85,5.

b)To determine the probability of a hand with at least one ace and face we will track the same road again.

(32/52)*(31/51)*(30/50)*(29/49)*(28/48)=0,0775

Then, we need to deduct this value from the probability 1

1-0,0775=0,922

The probability of the hand with at least one ace and one face is %92,2.

3 0
3 years ago
Help please . Thank you
MArishka [77]
The general form is ax²+bx+c=0,
so at least we know b has to be 0. None of the values match unless we multiply everything by 4. That leads to answer B, a=1, b=0 and c=20
7 0
3 years ago
Please help
MakcuM [25]
Hello there!

To find this, we must simplify this equation.

first, let's simplify the right side

-1 * x = -x

-1 * 5 = -5

Now, we have: y -3 = -x -5

Now we must add + 3 to each side to get rif of the negative three

now we have y = -x - 2

So, your answer is B.) y= -1x - 2

I hope my answer was of assistance!

~ Fire
7 0
3 years ago
Read 2 more answers
1. In this figure, line m is parallel to line n, and p is a
mariarad [96]

Answer:

4

Step-by-step explanation:

picture attached as explanation

We can see through alternate interior and exterior angles, corresponding angles, and vertical angles what the measures are.

4 0
4 years ago
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