Answer:
Dude, where's the picture?
He actually borrowed P=21349-3000=18349 (present value)
Assume the monthly interest is i.
then future value due to loan:
F1=P(1+i)^n=18349(1+i)^(5*12)=18349(1+i)^60
future value from monthly payment of A=352
F2=A((1+i)^n-1)/i=352((1+i)^60-1)/i
Since F1=F2 for the same loan, we have
18349(1+i)^60=352((1+i)^60-1)/i
Simplify notation by defining R=1+i, then
18349(R^60)-352(R^60-1)/(R-1)=0
Simplify further by multiplication by (R-1)
f(R)=18349*R^60*(R-1)-352(R^60-1)=0
Solve for R by trial and error, or by iteration to get R=1.004732
The APR is therefore
12*(1.004732-1)=0.056784, or 5.678% approx.
Answer:
x = 5
Step-by-step explanation:
You want to find x such that ...
x^2 +(x +1)^2 = 61
2x^2 +2x -60 = 0 . . . . . simplify, subtract 61
x^2 +x -30 = 0 . . . . . . . divide by 2
(x +6)(x -5) = 0 . . . . . . . . factor; solutions will make the factors be zero.
The relevant solution is x = 5.
K would be the 180 anti clock and up to
