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3 years ago

Please help using law of cosines!

Mathematics

1 answer:

Tamiku [17]3 years ago

6 0

Answer:

∠ A ≈ 48°

Step-by-step explanation:

Using the Cosine rule to find an angle

cosA = $\frac{b^2+c^2-a^2}{2bc}$

with a = 10, b = 13 and c = 11

cosA = $\frac{13^2+11^2-10^2}{2(13)(11)}$

= $\frac{169+121-100}{286}$

= $\frac{190}{286}$ , thus

A = $cos^{-1}$ ( $\frac{190}{286}$ ) ≈ 48° ( to the nearest degree )

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One of the legs of a right triangle measures 7 cm and its hypotenuse measures 12 cm.

Oksana_A [137]

Answer:

AC ≈ 9,7sm

Step-by-step explanation:

AB=7 One side of a right triangle

BC=12 Hypotenuse of a right triangle

AC=?=x The other side of a right triangle

x²+7²=12²

x²=144-49

x²=95

x=√(95) ≈ 9,7

AC ≈ 9,7sm

3 0

2 years ago

Greg borrowed $100 from his parents. After he did some chores, they reduced the amount of his debt by $25.

Mariana [72]

Answer:

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2 years ago

Pepsi [2]

Answer:

B. x = 2

Step-by-step explanation:

Answer:

x = 2

Step-by-step explanation:

check by substituting each given value of x into the function

x = 0 ⇒ y = × 0² = 0

hence (0, 0) is correct

x = 2 ⇒ y = × 4 = 3

hence (2, 4 ) is incorrect

x = 3 ⇒ y = × 9 = 6

hence (3, 6 ) is correct

x = 5 ⇒ y = × 25 = 18

hence (5, 18 ) is correct

7 0

2 years ago

If the trapezoid on the grid below is translated by using the rule (x,y)-> (x-4,y-3) what will be the coordinates of B’?

vesna_86 [32]

Answer:

B'(3, 5)

Step-by-step explanation:

Rule for the translation of a point (x, y) by 'h' units left and 'k' units upwards,

(x, y) → (x - h, y + k)

If h = 4 and k = 3,

$(x, y)\rightarrow(x-4,y+3)$

Following this rule coordinates of the image point of B will be,

B(7, 2) → B'(7 - 4, 2 + 3)

→ B'(3, 5)

Therefore, coordinates of the image point B' will be,

B'(3, 5)

6 0

2 years ago

Simplify 7 1/3t−(10 2/3t−6) pls

Flura [38]

Answer:

$-\frac{10t}{3}+6$

Step-by-step explanation:

$7 \frac{1}{3}t-(10 \frac{2}{3} t-6)$

Convert $7\frac{1}{3}$ to a mixed number

$7\frac{1}{3}=\frac{7\cdot 3+1}{3}$

$=\frac{22}{3}$

$\bold{\frac{22}{3}t-\left(10\frac{2}{3}t-6\right)}$

Convert $10\frac{2}{3}$ into a mixed number

$10\frac{2}{3}=\frac{10\cdot 3+2}{3}$

$=\frac{32}{3}$

$\bold{\frac{22}{3}t-\left(\frac{32}{3}t-6\right)}$

$=\frac{22t}{3}-\frac{32t}{3}+6$

$\bold{=\frac{-10t}{3}+6}$

Terms

Follow the PEMDAS order of operation:

P = Parenthesis
E = Exponents
M = Multiplication
D = Division
A = Addition
S = Subtraction

You do these steps in the order for which the equation comes. For example, start with the exponents if there are not any parentheses.

6 0

1 year ago