x + 8 > 14
x > 14 - 8
x > 6
Basically, any number above 6 is an answer
Hello,
q(x)=6x^3+19x²-15x-28
28/6=14/3
Potentiel roots are +/-1/3, +/- 2/3,+/-7/3, +/- 14/3
You end up with a false statement.
4 has never equaled 3.
Hope it helps!
Good lcuk with your studies! :)
Hope it helps! :)
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An integer is a whole number. Sum means to add and since they are consecutive, there is only a difference of 1 between them.
1) 21 + 23: not consecutive
2) 23+24= 47: has to be at least 46
3) 22+23= 45: has to be at least 46
4) 24+25= 49: has to be at least 46
So we have two possibilities: either #2 or #4. Find least possible pair of integers.
x= first integer
x+1= second integer
x + (x+1) >= 46
2x + 1 >=46
2x>=45
x>=22.5
Answer:
The first integer has to be greater than or equal to 22.5. Since integers are whole numbers, round up to the next whole number. The least possible integers are #2) 23 and 24.
Hope this helps! :)
Answer:
175/25
Step-by-step explanation:
i think this answers you question