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WARRIOR [948]
3 years ago
11

Which of the following are true of bar graphs?

Mathematics
2 answers:
AleksandrR [38]3 years ago
6 0
Your answer I'm pretty sure is B there gaps between bars because when you make data you space them out (gaps) so no one will get confused which is which about the numbers.

Your answer is B.
sladkih [1.3K]3 years ago
3 0
Data is displayed in intervals would be your correct answer.
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Instructions: Using the image, find the distance between the points given on the graph.​
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Answer:

3-1 = 2 units is the distance between the points.

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For the school concert band performance, student tickets cost $8 each and adult tickets cost $12 each. The sellers collected $3,
grigory [225]
200 adult tickets were sold, and 100 student tickets were sold
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Can someone please help me!
Anuta_ua [19.1K]

To solve the formula for v1, we must get this variable alone on one side of the equation. To do this, we use the reverse order of operations to move the other variables to the other side of the equation.

First, we begin by multiplying both sides of the equation by t, so that we can get rid of the denominator on the right side.

a = (v1 - v0)/t

a(t) = v1 - v0

Next, we must add v0 to both sides of the equation. This will get the variable v1 completely alone on the right side of the equation, giving us our answer.

(at) + v0 = v1

We should rearrange the equation so that v1 is the left side of the equation.

v1 = at + v0 (your answer)

Hope this helps!

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3 years ago
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The height of a rocket a given number of seconds after it is released is modeled by . What does t represent?
lutik1710 [3]

\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \\\\ ~~~~~~\textit{in meters} \\\\ h(t) = -4.9t^2+v_ot+h_o \end{array}  \quad  \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases}

6 0
4 years ago
John and Becky measured the circle-shaped part of a sun they drew on the sidewalk. The diameter of the circle is 56 centimeters.
raketka [301]

Answer:

The approximate area of the circle is <u>2462 centimeters²</u>.

Step-by-step explanation:

Given:

John and Becky measured the circle-shaped part of a sun they drew on the sidewalk. The diameter of the circle is 56 centimeters.

Now, to get the area of the circle approximately.

Diameter of the circle = 56 centimeters.

<em>So, the radius </em><em>(r)</em><em> of the circle</em> = \frac{Diameter}{2} =\frac{56}{2}=28\ centimeters.

Using 3.14 for π.

Now, to get the area of circle by putting formula:

Area=\pi r^2\\\\Area=3.14\times 28^2\\\\Area=3.14\times 784\\\\Area=2461.76\ centimeters^2.

<u><em>Approximately the area of the circle = 2462 centimeters².</em></u>

Therefore, the approximate area of the circle is 2462 centimeters².

3 0
3 years ago
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