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Keith_Richards [23]
3 years ago
8

Which of the following pairs of polnts are on the same horizontal line?

Mathematics
2 answers:
ohaa [14]3 years ago
5 0

Answer:

A

Step-by-step explanation:

aalyn [17]3 years ago
4 0

Answer:

The answer is A. (-2,-2 and (2,2)

Step-by-step explanation:

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Hello, how can I find the slope of 4y+6x=2?
omeli [17]

You solve for y

4y=-6x+2

y=-6/4x+2

y=-2/3x+2


Slope is -2/3, the number in front of x is the slope.


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Write the equation of the line that passes through (3, 4) and (2, −1) in slope-intercept form.
lys-0071 [83]

Answer:

5

Step-by-step explanation:

Slope equation is (y2-y1)/(x2-x1)

(-1-4)/(2-3)

-5/-1

5

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3 years ago
Ten recorded 8 songs in 49min how many minutes is each song?
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49/8=6 (nearest whole number)
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2 years ago
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g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa
adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is  \sigma =  0.0133

Step-by-step explanation:

From the question we are told that

   The upper specification is  USL  =  1.68 \ mm

    The lower specification is  LSL  = 1.52  \  mm

     The sample mean is  \mu =  1.6 \  mm

     The standard deviation is  \sigma =  0.03 \ mm

Generally the capability index in mathematically represented as

             Cpk  =  min[ \frac{USL -  \mu }{ 3 *  \sigma }  ,  \frac{\mu - LSL }{ 3 *  \sigma } ]

Now what min means is that the value of  CPk is the minimum between the value is the bracket

          substituting value given in the question

           Cpk  =  min[ \frac{1.68 -  1.6 }{ 3 *  0.03 }  ,  \frac{1.60 -  1.52 }{ 3 *  0.03} ]

=>      Cpk  =  min[ 0.88 , 0.88  ]

So

         Cpk  = 0.88

Now from the question we are asked to evaluated the value of  standard deviation that will produce a  capability index of 2

Now let assuming that

         \frac{\mu - LSL  }{ 3 *  \sigma } =  2

So

         \frac{ 1.60 -  1.52  }{ 3 *  \sigma } =  2

=>    0.08 = 6 \sigma

=>     \sigma =  0.0133

So

        \frac{ 1.68  - 1.60 }{ 3 *  0.0133 }

=>      2

Hence

      Cpk  =  min[ 2, 2 ]

So

    Cpk  = 2

So    \sigma =  0.0133 is  the value of standard deviation required

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3 years ago
What is the minimum value of this function
Luden [163]

Answer:

I believe its -8

Step-by-step explanation:

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