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stepan [7]
3 years ago
15

Use the information given to find a convenient class width. Then list the class boundaries that can be used to create a relative

frequency histogram. (Round your class width up to the nearest multiple of 5. Use the minimum value as the smallest class boundary. Enter your class boundaries as a comma separated list.)
Mathematics
1 answer:
notka56 [123]3 years ago
6 0

Answer:

hello some information is missing below is the missing information

8 classes for n = 75 measurements; minimum value = 20; maximum value = 175

answer : width = 20

               class boundary : 20,40,60,80,100,120,140,160,180

Step-by-step explanation:

Using the information given the convenient class width

= (maximum value - minimum value) / number of class

= ( 175 - 20 ) / 8

= 155 / 8 = 19.375 to the nearest multiple of 5 =  20

Using the minimum value as the smallest class boundary

the class boundary will be :

20,40,60,80,100,120,140,160,180

since the maximum value 175

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Step-by-step explanation:

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3 years ago
ILL MARK BRAINLIST IF ITS RIGHT.
erastovalidia [21]

Answer:

Step-by-step explanation:

The formula you should use is

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3 0
3 years ago
A rectangle has a height of 5 and a width of 4x2– 2x - 6.
joja [24]

Answer:

area = 20x^2 - 10x - 30

Step-by-step explanation:

5(4x2 - 2x - 6)

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5 0
3 years ago
A television game has 6 shows doors, of which the contests must pick 2. behind two of the doors are expensive cars, and behind t
Katyanochek1 [597]
The answer to this question:
One car probability 82/120
No car probability = 24/120
At least one car probability= 96/120

I will focus answering the 3 doors probability since the 2nd door problem is solved in the previous problem. (brainly.com/question/5761449)

No car condition
1. 1st door consolation, 2nd door consolation=, 3rd door consolation= 4/6 * 3/5 * 2/4= 24/120
This was also can be found by: (4!/1!)/ (6!/3!) = 24/120

(At least one car probability)  is the opposite of (no car probability) In this case, the easier way is 
100% - (no car probability) = 120/120 - 24/120= 96/120

One car probability is (At least one car probability) - (2 car probability). It will be easier to count the 2 car probability and subtract the (At least one car probability) 
Two car condition:
1. 1st door car, 2nd door car, 3rd door consolation = 2/6 * 1/5 * 4/4 =8/ 120
2.1st door car, 2nd door consolation, 3rd door car =2/6 * 4/5 * 1/4 = 8/120
3. 1st door consolation, 2nd door car, 3rd door car= 4/6 * 2/5 * 1/4= 8/120
The total probability will be 8/120+ 8/120 + /120= 24/120
This was also can be found by: (2!) (4!/2!)/ (6!/3!) = 24/120

One car probability =  (At least one car probability) - (2 car probability)= 96/120-24/120= 82/120
3 0
3 years ago
How would the expression x^2-4 be rewritten using Difference of Squares?
Anna [14]
<span>a2 – b2 = (a + b)(a – b) or (a – b)(a + b).
This is the 'Difference of Squares' formula we can use to factor the expression.

In order to use the </span><span>'Difference of Squares' formula to factor a binomial, the binomial must contain two perfect squares that are separated by a subtraction symbol.

</span><span>x^2 - 4 fits this, because x^2 and 4 are both perfect squares, and they are separated by a subtraction symbol.
All you do here to factor, is take the square root of each term.

√x^2 = x
√4 = 2

Now that we have our square roots, x and 2, we substitute these numbers into the form (a + b)(a - b).
</span>
<span>(a + b)(a - b)
(x + 2)(x - 2)

Our answer is final </span><span>(x + 2)(x - 2), which can also be written as (x - 2)(x + 2), it doesn't make a difference which order you put it in.

Anyway, Hope this helps!!
Let me know if you need help understanding anything and I'll try to explain as best I can.</span>
3 0
3 years ago
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