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3 years ago

Evaluate the expression. × , when =13 and =12

Mathematics

2 answers:

densk [106]3 years ago

7 0

Answer:

The answer you would be looking for is 156

Step-by-step explanation:

If M=13 and N=12 then it would just be 12x13 I hoped this helped

fredd [130]3 years ago

7 0

The answer is C! it’s 156

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What's 60,488 rounded to the nearest ten thousand?

Lubov Fominskaja [6]

the answer is 60000 to the nearest 1000

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3 years ago

According to the graph what is the value of x when g(x)=4

Serhud [2]

Answer:

x=2

Step-by-step explanation:

we know that

according to the graph

when g(x)=4

the value of x=2

see the attached figure to better understand the problem

7 0

3 years ago

HELP ME DO THIS PLZ

cestrela7 [59]

Answer:

It landed at a height of 14 feet

Step-by-step explanation:

Given

$y = -\frac{1}{8}x^2 +4x$ --- Path of a t-shirt

$3y = 2x - 14$ --- height of bleachers

Required

Height when t-shirts land in bleachers

$3y = 2x - 14$

Make y the subject

$y = \frac{2}{3}x - \frac{14}{3}$

Substitute $y = \frac{2}{3}x - \frac{14}{3}$ in $y = -\frac{1}{8}x^2 +4x$

$\frac{2}{3}x - \frac{14}{3} = -\frac{1}{8}x^2 +4x$

Multiply through by 24

$16x- 112 = -3x^2 +96x$

Express as:

$3x^2 + 16x -96x- 112 = 0$

$3x^2 -80x- 112 = 0$

Using a calculator:

$x = 28$ or $x = -\frac{4}{3}$

x can not be negative:

So:

$x = 28$

Substitute $x = 28$ in $y = -\frac{1}{8}x^2 +4x$ to calculate the height it landed

$y = -\frac{1}{8} * 28^2 + 4 * 28$

$y = 14$

3 0

2 years ago

Uh I'm confused on how to do this may someone help?

vlada-n [284]

Answer:

Step-by-step explanation:

Use the distance formula

$\sqrt{(x_{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}}$

$\sqrt{(-2+7)^{2}+(4-4)^{2}}$

$\sqrt{5^{2}}=5$

You can also just subtract: -2-(-7) to get 5 because the y-values are the same

4 0

3 years ago

Read 2 more answers

A vertical pole is supported by two ropes staked to the ground on opposite sides of the pole. One rope is 8 meters long, and the

aniked [119]

Establish two right triangles, both with the height of the pole, h.

Call x the distance from the pole to one stake. Then the distance from the other stake to the pole is 6 -x.

Apply Pytagora's equation to both triangles.

1) h^2 = 7^2 - x^2

2) h^2 = 8^2 - (6-x)^2

Eaual 1 to 2

7^2 - x^2 = 8^2 - 6^2 +12x -x^2

12x = 7^2 -8^2 +6^2 = 49 -64 + 36 = 21

x = 1.75

Substitue x-value in 1

h^2 = 49 - (1.75)^2 = 45.94

h = sqrt(45.94) = 6.78

Answer: option d.

8 0

2 years ago

Read 2 more answers