Answer:
7x-17y
Step-by-step explanation:
We need to find the expression which represents the difference when (-2x+10y) is subtracted from (5x−7y) . Let the result is R.
So,
R = (5x−7y)-(-2x+10y)
Solving brackets as follows :
R = (5x−7y)+2x-10y
taking like terms together
R = (5x+2x)+(-7y-10y)
R = 7x-17y
Hence, when (-2x+10y) is subtracted from (5x−7y) the result is (7x-17y).
The simplified expression is 11r+2
Answer:
P(X > 5) = 0.1164 to 4 d.p.
The parameters are defined in the explanation.
Step-by-step explanation:
This is a binomial distribution problem
Binomial distribution function is represented by
P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ
n = total number of sample spaces = number of potential hires = 10
x = Number of successes required = number of potential hires that have prior call centre experience = more than half; that is, x > 5
p = probability of success = probability that any potential hire will have experience = (11/30) = 0.367
q = probability of failure = probability that any potential hire will NOT have experience = 1 - p = 1 - 0.367 = 0.633
P(X > 5) = P(X=6) + P(X=7) + P(X=8) + P(X=9) + P(X=10)
Inserting the parameters and computing the probabilities for each of those values of X,
P(X > 5) = 0.11641775484 = 0.1164 to 4 d.p.
Hope this Helps!!!
T's solve your equation step-by-step.<span><span><span>14</span><span>(<span><span>4x</span>+15</span>)</span></span>=24</span>Step 1: Simplify both sides of the equation.<span><span><span>14</span><span>(<span><span>4x</span>+15</span>)</span></span>=24</span><span><span><span><span>(<span>14</span>)</span><span>(<span>4x</span>)</span></span>+<span><span>(<span>14</span>)</span><span>(15)</span></span></span>=24</span>(Distribute)<span><span>x+<span>15/4</span></span>=24</span>Step 2: Subtract 15/4 from both sides.<span><span><span>x+<span>15/4</span></span>−<span>15/4</span></span>=<span>24−<span>154</span></span></span><span>x=<span>81/<span>4</span></span></span>
well, another way to word it will be, we know "x" and "y" are directly proportional, we also know that x = 6 when y = 42, what is "y" when x = 1?
![\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \textit{we know that } \begin{cases} x = 6\\ y =42 \end{cases}\implies 42 = k(6)\implies \cfrac{42}{6}=k\implies 7=k \\\\\\ \textit{therefore}\qquad \qquad \boxed{y = 7x} \\\\\\ \textit{when x = 1, what is \underline{y}?}\qquad y = 7(1)\implies y = 7](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Cqquad%20%5Ctextit%7Bdirect%20proportional%20variation%7D%20%5C%5C%5C%5C%20%5Ctextit%7B%5Cunderline%7By%7D%20varies%20directly%20with%20%5Cunderline%7Bx%7D%7D%5Cqquad%20%5Cqquad%20%5Cstackrel%7B%5Ctextit%7Bconstant%20of%20variation%7D%7D%7By%3D%5Cstackrel%7B%5Cdownarrow%20%7D%7Bk%7Dx~%5Chfill%20%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Ctextit%7Bwe%20know%20that%20%7D%20%5Cbegin%7Bcases%7D%20x%20%3D%206%5C%5C%20y%20%3D42%20%5Cend%7Bcases%7D%5Cimplies%2042%20%3D%20k%286%29%5Cimplies%20%5Ccfrac%7B42%7D%7B6%7D%3Dk%5Cimplies%207%3Dk%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Btherefore%7D%5Cqquad%20%5Cqquad%20%5Cboxed%7By%20%3D%207x%7D%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Bwhen%20x%20%3D%201%2C%20what%20is%20%5Cunderline%7By%7D%3F%7D%5Cqquad%20y%20%3D%207%281%29%5Cimplies%20y%20%3D%207)
