Parameterize S by the vector function

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.
Compute the outward-pointing normal vector to S :

The integral of the field over S is then



I solved and the mean is 10
Answer:
0.611 = 61.1%
Step-by-step explanation:
'Percent (%)' means 'out of one hundred':
p% = p 'out of one hundred',
p% = p/100 = p ÷ 100.
Note:
100/100 = 100 ÷ 100 = 100% = 1
Multiply a number by the fraction 100/100,
... and its value doesn't change.
Calculate the percent value:
0.611 =
0.611 × 100/100 =
(0.611 × 100)/100 =
61.1/100 =
61.1%;
In other words:
1) Multiply that number by 100.
2) Add the percent sign % to it.
Answer:
closest answer = 81
Step-by-step explanation:
81/27 = 3
81/30= 2.7
81/45 = 1.8