$f(x) = 5x + 1\\\\subtitute\ x = 1\ to\ the\ equation\\\\f(1) = 5\cdot1 + 1 = 5 + 1 = 6\\----------------------\\f(x)=\dfrac{2x+3}{5}\to y=\dfrac{2x+3}{5}\ \ \ \ |multiply\ both\ sides\ by\ 5\\\\5y=2x+3\ \ \ \ |subtract\ 3\ from\ both\ sides\\\\2x=5y-3\ \ \ \ \ |divide\ both\ sides\ by\ 2\\\\x=\dfrac{5y-3}{2}\\\\f^{-1}(x)=\dfrac{5\cdot(-1)-3}{2}=\dfrac{-5-3}{2}=\dfrac{-8}{2}=-4\\---------------------\\3y-7=y+5\ \ \ |add\ 7\ to\ both\ sides\\3y=y+12\ \ \ \ |subtract\ y\ from\ both\ sides\\2y=12\ \ \ \ |divide\ both\ sides\ by\ 2\\y=6$

Answer: f(1) when f(x) = 5x + 1 and 3y - 7 = y + 5

6 0

3 years ago

Define local maximum value.

Natasha_Volkova [10]

In mathematical analysis, the maxima of a function, is the largest value of the function, either within a given range or on the entire domain of a function.

5 0

4 years ago

Pls help and do quick!

motikmotik

Answer:

If 50.24cm = Circumference

Radius = 8cm

If 50.24cm^2 = Area

Radius = 4cm

Step-by-step explanation:

50.24cm what? Circumference? Area?

π = 3.14

2πr = Circumference

50.24 / 2π = r

r = 8

πr^2 = Area

50.24 / π = r^2

r^2 = 16

r = 4

7 0

2 years ago