Answer:
The image of the point (1, -2) under a dilation of 3 is (3, -6).
Step-by-step explanation:
Correct statement is:
<em>What are the coordinates of the image of the point (1, -2) under a dilation of 3 with the origin.</em>
From Linear Algebra we get that dilation of a point with respect to another point is represented by:
(Eq. 1)
Where:
- Reference point with respect to origin, dimensionless.
- Original point with respect to origin, dimensionless.
- Dilation factor, dimensionless.
If we know that
,
and
, then the coordinates of the image of the original point is:
![\vec P' = (0,0) +3\cdot [(1,-2)-(0,0)]](https://tex.z-dn.net/?f=%5Cvec%20P%27%20%3D%20%280%2C0%29%20%2B3%5Ccdot%20%5B%281%2C-2%29-%280%2C0%29%5D)


The image of the point (1, -2) under a dilation of 3 is (3, -6).
A real world example is when a patient is injected with medicine until the concentration of the medicine in the blood is at its ideal level. Here is how you would graph it. In a table it would be on the left side, 123456, and on the right side, 1, 0.5, 0.25, 0.2, 0.15, 0.1
There is no table sow how are we supposed to help you?
Which equation? Sorry I don’t see one
It B. You enter 5 instead of x and calculate.