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3 years ago

A 66-meter garden row is divided into 44 equal-sized sections to plant onions.

1 answer:

8 0

You may represent this multiple ways.

1. 66/44 = m

2. 44m = 66

In both of these scenarios you have a total and equal parts.

The first one starts with a total and breaks it into equal parts.

The second choice shows 44 groups of a part totaling 66 meters.

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The population of a town is 13,000. It decreases at a rate of 5% per year. In about how many years will the population be less t

just olya [345]

This is an exponential decay problem.

Using the equation Y = a *(1-rate)^time

where Y is the future value given as 12,000 and a is the starting value given as 13,000.

The rate is also given as 5%.

The equation becomes:

12,000 = 13,000(1-0.05)^x

12,000 = 13,000(0.95)^x

Divide each side by 13000:

12000/13000 = 0.95^x/13000

12/13 = 0.95^x

Use the natural log function:

x = ln(12/13) / ln(0.95)

x = 1.56 years. ( this will equal 12,000

Round to 2 years it will be less than 12000.

3 0

3 years ago

Part A

kap26 [50]

Reflecting the polygon FGHI across the line involves flipping the line across the line y = -1

<h3>How to reflect the polygon?</h3>

The coordinates are given as:

F(2, – 1), G(5,2), H(8, 3), and I(6, 0)

The line of reflection is given as:

y = -1

To reflect the line, we apply the following rule of reflection

(x,y) $\to$ (x,-y-2)

So, we have the following coordinates of the image

F' = (2, – 1)

G' = (5,-4)

H' = (8, -5)

I' = (6, -2)

See attachment for the image of the reflected polygon

Read more about reflection at:

brainly.com/question/4289712

4 0

1 year ago

A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square

kondaur [170]

This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

$V = xxy = x^{2}y$

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = $x^{2}$

Surface area of the rectangular sides = $4xy$

Therefore, the total area of the cube is:

$A = 48 ft^{2} = x^{2} + 4xy$

Isolating the variable y in terms of x:

$y = \frac{48- x^{2} }{4x}$

Substituting this value in V:

$V = x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}$

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

$\frac{dv}{dx} = 48-3x^{2} =0$

Solving for x:

$x = \sqrt{\frac{48}{3}} = \sqrt{16} = 4$

Solving for y:

$y = \frac{48- 4^{2} }{(4)(4)} = 2$

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width = 4 ft
Height = 2 ft

And its volume is:

$V = (4^{2} )(2) = 32 ft^{3}$