If they together at the same rate for the same amount of time, they will solve 48 math problems,
From the question, we can see that two mathletes solve 32 math problems in a certain amount of time, this can be written as:
- 2 mathletes = 32 math problems
In order to determine the number of problems for 3 mathletes, this is expressed as:
DIvide both expressions:
Cross multiply
2x = 3* 32
x = 3 * 16
x = 48math problems
Hence if they together at the same rate for the same amount of time, they will solve 48 math problems,
Learn more on proportion here: brainly.com/question/1496357
Answer:
the value of the printer is going down over the years because it is getting older. all you need to do for this is label the x and y axis with the nbers on the graph and then fill it in
has ur teacher gone over how to fill in graphs yet?
You are given the height of the building and the length of the shadow the building gives, so you can set that up as a proportion of Height of building over the length of the shadow so 31/28.
Now you can set the same proportion for Julian, using X for her height, so you would have x/6.
To solve for her height, set the two proportions equal and solve for x:
31/28 = x/6
Cross multiply:
31 * 6 = 28 *x
186 = 28x
Divide both sides by 28:
x = 186 / 28
x = 6.64 feet tall
The answer is 1/6 because 1 /2 × 1/3 =1/6
