Answer:
19 < x < 31
Step-by-step explanation:
The range for the third side is
25-6 < x < 25+6
19 < x < 31
Take the other two sides and subtract and take the other two sides and add
The question is incomplete. Here is the complete question:
What is the volume of this triangular prism?
Base length = 22.4 cm
Height = 18.1 cm
Length = 28 cm
A) 313.6 cm3
B) 506.8 cm3
C) 5,676.16 cm3
D) 11,352.32 cm3
Answer:

Step-by-step explanation:
Given:
The base of the prism is triangular with base length equal to 22.4 cm and height 18.1 cm. The length of the prism is 28 cm.
The volume of a triangular prism is defined by the formula:

Here, the base is triangular and the area of a triangle is:

Therefore, the volume of the triangular prism is given as:

Now, plug in the given values and solve for the volume 'V'.

Therefore, the correct answer is the third option.

Answer:
Its either 10 to the power of 6 or ten to the power of 5
Step-by-step explanation:
...
The true statement about this information is that: A. It is both a relation and a function.
<h3>What is a function?</h3>
A function can be defined as a mathematical expression which can be used to define and represent the relationship that exist between two or more variables in a population.
In this context, we can infer and logically deduce that the true statement about this information collected by Jen is that it's both a relation and a function because it indicates a relationship between two variables.
Read more on function here: brainly.com/question/4246058
#SPJ1
Answer:
Coffee = $2.00
Juice = $1.50
Doughnut = $1.00
Step-by-step explanation:
Given
Let:

So, we have:
Anna

Barry

Cathy

Required
The price of each
We have:



Make c the subject in: 

Substitute
in
and 

![2[5.00 - 3d] + j + 2d = 7.50](https://tex.z-dn.net/?f=2%5B5.00%20-%203d%5D%20%2B%20j%20%2B%202d%20%3D%207.50)

Make j the subject



![3[5.00 - 3d] + j + 4d = 11.50](https://tex.z-dn.net/?f=3%5B5.00%20-%203d%5D%20%2B%20j%20%2B%204d%20%3D%2011.50)

Make j the subject


So, we have:
and 
Equate both values of j

Collect like terms


Substitute
in 




To solve for c, we substitute
in 


Solve for c

