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kati45 [8]
3 years ago
7

Which of the values for x and y make the equation 2x + 3y + 4 = 15 true?

Mathematics
1 answer:
natima [27]3 years ago
7 0
2(1)+3(3)+4=15
2+9+4=15
Or
2(4)+3(1)+4=15
8+3+4=15
So either one would work
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Isabella has a 22 ounce cola. She drinks 17 ounces. Enter the percentage of ounces Isabella has left of her cola. Round your ans
jenyasd209 [6]

Answer:

<u>22.73%</u> of ounces Isabella has left of her cola.

Step-by-step explanation:

Given:

Isabella has a 22 ounce cola. She drinks 17 ounces.

Now, to find the percentage of ounces Isabella has left of her cola.

Total ounces of cola = 22.

Ounces of cola Isabella drink = 17.

So, the ounces of cola she left:

<em>Total ounces of cola - ounces of cola Isabella drink.</em>

=22-17

=5\ ounces.

<u><em>Thus, 5 ounces of cola she left.</em></u>

Now, to get the percentage of cola she left:

\frac{5}{22}\times 100

=\frac{500}{22}

=22.727\%.

<u>Rounding the percentage to the nearest hundredths is 22.73%.</u>

Therefore, 22.73% of ounces Isabella has left of her cola.

7 0
3 years ago
See the question below.
zheka24 [161]

your answer is B i hope this helpss

4 0
3 years ago
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Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
ella [17]

Answer: 20%??? I don't know Honestly

Step-by-step explanation:

6 0
3 years ago
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vampirchik [111]
The answer is 13 hope I helped
5 0
3 years ago
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A specimen of charcoal found at Stonehenge contains 63% as much Carbon-14 as a sample of present-day charcoal. What is the age o
seraphim [82]
Since we are given with the identity of the chemical as Carbon-14, we obtain the half-life of the chemical from a reliable source and get a value of 5730 years. The equation that we are going to use for this item is,
                              A(t)/A(0) = (0.50)^(n/5730)
where A(t) is the current amount, A(0) is the initial amount and n is the number of years. We know from the given that the ratio of A(t) and A(0) is equal to 0.63. Substituting this to the given,
                                0.63 = 0.50^(n/5730)
                                        n = 3819.48 
Thus, the sample is approximately 3819.5 years old. 
5 0
3 years ago
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