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IceJOKER [234]
3 years ago
5

6y=x-18 3y=-15x+15 What is the value of x?

Mathematics
1 answer:
VLD [36.1K]3 years ago
3 0

Answer:

Step-by-step explanation:

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What is the answer to the question " 6(5x(41-36)-(8+14))
alisha [4.7K]
So  41-36=5, 5x5=25, which makes it 6(25-(8+14)). So then it's 6(25-22), which is 6x3, which is 18. (So 18 is the answer). 
5 0
4 years ago
− 3 ( p + 2 ) = − 30 − 3(p + 2) = − 30
Katena32 [7]

Answer: y=Mx+b

Step-by-step explanation:

G

7 0
3 years ago
Which statement is true about point F? a.F is the midpoint of AA' because bisects AA'. b.F is the midpoint of EG because AA' bis
Dimas [21]

Answer:

The correct option is;

a. F is the midpoint of \overline{AA'} because line \overline{EG} bisects \overline{AA'}

Step-by-step explanation:

Here, since we have that the triangle is reflected across EG therefore the location of the point F which is along EG bisects the line \overline{AA'} as the  dimensions of the line from A to F must be equal to the dimension of the line that extends from A' to F

Therefore the point F is the midpoint of \overline{AA'} because line \overline{EG} bisects \overline{AA'}.

7 0
3 years ago
Find the common difference of the arithmetic sequence, the next three terms, the equation, and the term given for 8, 10, 12, 14
fredd [130]

Answer:

see explanation

Step-by-step explanation:

In an arithmetic sequence the common difference d is

d = a₂ - a₁ = 10 - 8 = 2

To obtain the next term in the sequence add d to the previous term, that is

a₅ = 14 + 2 = 16

a₆ = 16 + 2 = 18

a₇ = 18 + 2 = 20

The next 3 terms in the sequence are 16, 18, 20

The n th term equation for an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 8 and d = 2, thus

a_{n} = 8 + 2(n - 1) = 8 + 2n - 2 = 2n + 6

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cbf%20%5Chuge%20x%20%7B%7D%5E%7B2%7D%20%20%2B%205%20%3D%206" id="TexFormula1" title=" \bf
ira [324]

<u>Given</u> :

  • x² + 5 = 6

<u>Subtract 5 from each side</u> :

  • x² + 5 - 5 = 6 - 5
  • x² = 1

<u>Take the root on each side</u> :

  • √x² = √1
  • x = ±1

<u>Hence, the values of x are</u> :

  • \fbox {x = 1}
  • \fbox {x = -1}
5 0
2 years ago
Read 2 more answers
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