V = arh for h<br> Helppppppppp

Can you help me, please?

julsineya [31]

Answer:

The first one is two over four

Step-by-step explanation:

8 0

3 years ago

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PLZZZZZZZZZZ I WILL GIVE BRAINLIEST AND 15PTS!!!!!!!!!!!!!!

vazorg [7]

Answer: ( 0, 2 )

Step-by-step explanation:

You have to put coordinates of each graph on these equations y = -x + 2 and y = (1/2)x + 2. If putting coordinates satisfies both equations, then that coordinate will be the solution.

For example, let's put (0, 2) to equations.

y = -x + 2

2 = -0 + 2

2 = 2, true

y = (1/2)x + 2

2 = (1/2) × 0 + 2

2 = 2, true

So, ( 0, 2 ) is the solution.

7 0

3 years ago

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Without finding the inverse of the function, determine the range of the inverse of f left parenthesis x right parenthesis equals

natta225 [31]

c

The domain of the function is all real numbers greater than or equal to 0.

The range of the function is all real numbers greater than or equal to −1.

The range of the function is all real numbers less than or equal to 0.

The domain of the function is all real numbers less than or equal to 0

7 0

2 years ago

Please help. 100 points to best answer!!!

Irina-Kira [14]

1. The slope of a line that is perpendicular to a line whose equation

is 5y = 10 + 2x is $\frac{-5}{2}$

2.

The line y = 2x - 1 is neither parallel nor perpendicular to the line

y = -2x + 3

The line y = -2x + 5 is parallel to the line y = -2x + 3

The line y = $\frac{1}{2}$ x + 7 is perpendicular to the line

y = -2x + 3

3. The equation of the line that passes through the point (5 , -4) and

is parallel to the line whose equation is 2x + 5y = 10 is

y = $\frac{-2}{5}$ x - 2

Step-by-step explanation:

Let us revise some rules

The slope-intercept form of the linear equation is y = m x + b, where m is the slope of the line and b is the y-intercept
The slopes of the parallel lines are equal
The product of the slopes of the perpendicular lines is -1

1.

∵ The equation of the line is 5y = 10 + 2x

- Put the equation in the form of slope-intercept

- Divide both sides by 5

∴ y = 2 + $\frac{2}{5}$ x

∴ m = $\frac{2}{5}$

∴ The slope of the line is $\frac{2}{5}$

∵ The product of the slopes of the perpendicular lines is -1

- That means if the slope of a line is m, then the slope of the

perpendicular line to this line is $\frac{-1}{m}$

∵ The slope of the line = $\frac{2}{5}$

∴ The slope of the perpendicular line $\frac{-5}{2}$

The slope of a line that is perpendicular to a line whose equation

is 5y = 10 + 2x is $\frac{-5}{2}$

2.

∵ Line a is represented by the equation y = -2x + 3

∴ m = -2

∴ The slope of the line is -2

∵ The equation of the line is y = 2x - 1

∴ m = 2

∴ The slope of the line is 2

∵ 2 ≠ -2

∵ 2 × -2 ≠ -1

∴ The two lines neither parallel nor perpendicular

The line y = 2x - 1 is neither parallel nor perpendicular to the line

y = -2x + 3

∵ The equation of the line is y = -2x + 5

∴ m = -2

∴ The slope of the line is -2

∵ The slopes of the lines are equal

∴ The two lines are parallel

The line y = -2x + 5 is parallel to the line y = -2x + 3

∵ The equation of the line is y = $\frac{1}{2}$ x + 7

∴ m = $\frac{1}{2}$

∴ The slope of the line is $\frac{1}{2}$

∵ $\frac{1}{2}$ × -2 = -1

∵ The product of the slopes of the lines is -1

∴ The two lines are perpendicular

The line y = $\frac{1}{2}$ x + 7 is perpendicular to the line

y = -2x + 3

3.

∵ The equation of a line that is parallel to the line whose equation

is 2x + 5y = 10

∴ Their slopes are equal

- Put the equation in the form of y = mx + b to find m

∵ 2x + 5y = 10

- Subtract 2x from both sides

∴ 5y = 10 - 2x

- Divide both sides

∴ y = 2 - $\frac{2}{5}$ x

∴ m = $\frac{-2}{5}$

∴ The slope of the line is $\frac{-2}{5}$

∵ The form of the equation is y = mx + b

∵ m = $\frac{-2}{5}$

∴ y = $\frac{-2}{5}$ x + b

∵ The line passes through the point (5 , -4)

- Substitute the coordinates of the point in the equation to find b

∵ x = 5 , y = -4

∴ -4 = $\frac{-2}{5}$ (5) + b

∴ -4 = -2 + b

- Add 2 to both sides

∴ -2 = b

∴ y = $\frac{-2}{5}$ x - 2

The equation of a line that passes through the point (5 , -4) and

is parallel to the line whose equation is 2x + 5y = 10 is

y = $\frac{-2}{5}$ x - 2

Learn more:

You can learn more about the equation of a line in brainly.com/question/4152194

#LearnwithBrainly

8 0

3 years ago

Write the equation of the function g(x) if g(x) = f(x - 3) +1 and f(x) = x3 + 1.

stealth61 [152]

Answer:

Solution,

f(x) = $x^{3}$ + 1

Put x = x - 3,

f(x - 3) = $(x-3)^{3}$ + 1

Now,

g(x) = f(x - 3) + 1

or, g(x) =[ $(x-3)^{3}$ +1 ] + 1

or, g(x) = $x^{3} -9x^{2} + 27x - 1 + 1+1$

or, g(x) = $x^{3} - 9x^{2} +27x + 1$

6 0

3 years ago

V = arh for h Helppppppppp