The rise is 6
and the run is 4
Step-by-step explanation:
f(x) + n - move the graph n units up
f(x) - n - move the graph n units down
f(x + n) - move the graph n units to the left
f(x - n) - move the graph n units to the right
====================================================
We have f(x) = 2ˣ.
g(x) = f(x) + 1 - move the graph of f(x) one unit up.
<em>(look at the picture)</em>
In my opinion i think it’d be 9 cm
Answer:
For this one the parallel slope is going to be 2/5
Step-by-step explanation:
Answer:
<em>Corey stepped back 59.71 feet</em>
Step-by-step explanation:
<u>Right Triangles
</u>
They are a special type of triangle where one of its internal angles is 90°. The basic trigonometric equations stand in this type of triangles. If x is the adjacent leg of a given angle
, and y is the opposite leg to the same angle, then
:
![\displaystyle tan\theta=\frac{y}{x}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20tan%5Ctheta%3D%5Cfrac%7By%7D%7Bx%7D)
We can solve for x to get
![\displaystyle x=\frac{y}{tan\theta}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Cfrac%7By%7D%7Btan%5Ctheta%7D)
Corey estimates the height of the tree to be 80 feet. This means we know y=80 and
. Let's find the horizontal distance at which Corey is looking at the bald eagle:
![\displaystyle x_1=\frac{80}{tan68^o}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x_1%3D%5Cfrac%7B80%7D%7Btan68%5Eo%7D)
![x_1=32.32\ feet](https://tex.z-dn.net/?f=x_1%3D32.32%5C%20feet)
Now Corey moves back to watch the very same tree at an elevation angle of 41°. The tree has the same height, so
![\displaystyle x_2=\frac{80}{tan41^o}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x_2%3D%5Cfrac%7B80%7D%7Btan41%5Eo%7D)
![x_2=92.03\ feet](https://tex.z-dn.net/?f=x_2%3D92.03%5C%20feet)
Now we can know the distance Corey walked back by subtracting both distances
![x=x_2-x_1=92.03-32.32=59.71\ feet](https://tex.z-dn.net/?f=x%3Dx_2-x_1%3D92.03-32.32%3D59.71%5C%20feet)
![\boxed{\text{Corey stepped back 59.71 feet}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctext%7BCorey%20stepped%20back%2059.71%20feet%7D%7D)