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lisabon 2012 [21]
4 years ago
10

From a point P outside line segment AB =6cm, construct a line PQ parallel to line segment AB.​

Mathematics
1 answer:
goldfiish [28.3K]4 years ago
4 0

Answer:

We drawn the graph.

Step-by-step explanation:

We have a line segment AB = 6cm and a point P outside that a line segment.  

We want to construct a line PQ that is parallel to  line segment AB.

If PQ is parallel to longer AB, this means that a line PQ is equidistant from  line segment AB everywhere.  

We use the geogebra.org site to draw it.

We drawn the graph.

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ludmilkaskok [199]

Answer:

x^{12} =400

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Step-by-step explanation:

x^{6} =20

x^{12} =(x^{6} )^{2} =20^{2} =400

w^{10} =20

w^{-10} =\frac{1}{w^{10} } =\frac{1}{20}

x^{12} *w^{-10} =400*\frac{1}{20} =20

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The best angle relationship that describes angles BAC and EAF is supplementary angles

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