Question

What is the equation of a circle with center (-3, -1) that contains the point (1, 2)? (x + 3)2 + (y + 1)2 = 25 (x − 3)2 + (y − 1)2 = 36 (x + 3)2 + (y − 1)2 = 36 (x − 1)2 + (y − 2)2 = 25

Answer 1

Answer:

The answer to your question is the first option

Step-by-step explanation:

Data

C ( -3, -1)

P (1, 2)

Process

1.- Calculate the radius

r = $\sqrt{(2 + 1)^{2} + (1 + 3)^{2}}$

r = $\sqrt{3^{2} + 4^{2}}$

r = $\sqrt{9 + 16}$

r = $\sqrt{25}$

r = 5

2.- Substitute the center and the radius in the equation of the circle. Remember to change the signs of the center.

Equation

               (x - h)² + (y - k)² = r²

Substitution

                (x + 3)² + (y + 1)² = 5²

                (x + 3)² + (y + 1)² = 25