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Debora [2.8K]
3 years ago
7

Question 18 (5 points)

Mathematics
2 answers:
Alecsey [184]3 years ago
7 0

Answer:

D) x=-3, is your answer

Romashka [77]3 years ago
4 0

Answer:

The answer is letter D.

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Lisa and Lori each dried 1/3 of the glasses. What fraction of the glasses
Yuki888 [10]
3/3-1/3= 2/3 of the glasses
6 0
3 years ago
Which best summmarize the pyhagorean theorem
andre [41]

Answer: the sum of the squares of the lengths of the legs of a right triangle equal the square of the length of the hypotenuse

Step-by-step explanation: hope it helps

6 0
2 years ago
Let g(x) = 2x and h(x) = x2 + 4. Evaluate (h ∘ g)(1). 2 8 10 4
Klio2033 [76]
Hello!

You can solve this by plugging 1 into g(x) and plugging the result into h(x).

g(x) = 2x
g(1) = 2(1)
g(1) = 2

h(x) = 2x + 4
h(g(1)) = 2(2) + 4
h(g(1)) = 4 + 4
h(g(1)) = 8

Answer:
<span>(h ∘ g)(1) = 8</span>
8 0
3 years ago
Can someone please write this as a single logarithm and show work please and thank you
Mazyrski [523]

Answer:  

log_b(w^3y^4)

Step-by-step explanation:

To write the expression as a single logarithm, or condense it, use the properties of logarithms.  

1) The power property of logarithms states that log_ax^r = rlog_ax. In other words, the exponent within a logarithm can be brought out in front so it's multiplied by the logarithm. This means that the number in front of the logarithm can also be brought inside the logarithm as an exponent.  

So, in this case, we can move the 3 and the 4 inside the logarithms as exponents. Apply this property as seen below:

3log_bw+4log_by\\=log_bw^3+log_by^4

2) The product property of logarithms states that log_axy = log_ax+log_ay. In other words, the logarithm of a product is equal to the sum of the logarithms of its factors. So, in this case, write the expression as a single logarithm by taking the log (keep the same base) of the product of w^3 and y^4. Apply the property as seen below and find the final answer.  

log_bw^3+log_by^4\\=log_b(w^3y^4)

So, the answer is log_b(w^3y^4).

4 0
2 years ago
Solve 2x2 – 6x + 10 = 0 by completing the square.
Ugo [173]

Answer:

Step-by-step explanation:

2x^2-6x+10=0

2(x^2-3x)+10=0

2(x-(3/2))^2-9/4)+10=0

2(x-(3/2))^2+10-9/2=0

2(x-(3/2))^2+(20-9)/2=0

2(x-(3/2))^2+11/2=0

2(x-(3/2))^2=-11/2

square is always positive so there is no solution

5 0
2 years ago
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