X= a number
(2x+4)/3 + (x+2)= 20
Multiply everything by 3 to eliminate the fraction
(3/1)((2x+4)/3) + (3)(x+2)= (3)(20)
2x+4+3x+6= 60
5x+10=60
Subtract 10 from both sides
5x=50
divide both sides by 5
x=10
Check:
Substitute answer in original equation
(2x+4)/3 + (x+2)= 20
(2(10)+4)/3+(10+2)= 20
(20+4)/3+12= 20
24/3+12= 20
8+12= 20
20=20
Hope this helps! :)
Answer:

Step-by-step explanation:
One of the rules of logarithms is ...
log(a^b) = b·log(a)
So ...

Answer:
Step-by-step explanation:
c(t)=40:0≤t≤400
=40+0.50 (t-400):t≥400
Do one hundred and twenty nine divided by three and you will get your answer
Answer:
2
Step-by-step explanation:
If you divide 0 by any number you will get 0
If you will substitute x for 2 you will have:
2-2/2+2=0/4=0