All categories

3 years ago

25t-13=-24t-30 for t

Mathematics

2 answers:

EastWind [94]3 years ago

3 0

Answer:

t = -17/49

Step-by-step explanation:

25t-13=-24t-30

Add 24t to each side

25t+24t-13=-24t+24t-30

49t-13=-30

Add 13 to each side

49t-13+13=-30+13

49t = -17

Divide each side by 49

49t/49 = -17/49

t = -17/49

Mamont248 [21]3 years ago

3 0

The right answer is - 17/49

please see the attached picture for full solution

Hope it helps

Good luck on your assignment

You might be interested in

MO is twice as long as MN. NO=36cm. Find MO and NM. Can you solve this problem? If so, give the solution. If not, explain why no

larisa86 [58]

Here’s my answer assuming N bisects MO and this is all on a straight line

If this is helpful, please mark me brainliest. :)

3 0

4 years ago

Imagine you have some workers and some handheld computers that you can use to take inventory at a warehouse. There are diminishi

Svet_ta [14]

Answer:

a. $1.03

b. $0.93

c. 0.98

d. 2 workers

Step-by-step explanation:

a. Given that:

1 computer : 1 worker : inventory 150 items per hour
1 computer : 2 workers : inventory 200 items per hour
1 computer : 3 workers : inventory 220 items per hour
1 computer : 4+ workers : fewer than 235 items per hour
Cost: $100 per computer ; $25 per worker

The fixed production factor in the warehouse is the computer used:

-One computer used, but the number of users is varied to inventory a specified number of items.

-The variable production factor is the number of workers assigned per one computer.

#The cost of inventorying a single item by one worker is:

$Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_1=\frac{125+30}{150}\\\\\\=1.03$

Hence, the cost of inventorying a single item is $1.03

b. Using the information provided above, the cost of inventorying a single item when two workers are assigned is :

$Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_2=\frac{125+2\times30}{200}\\\\\\=0.925$

Hence, the cost of inventorying a single item is $0.93

c.Using the information provided above, the cost of inventorying a single item when three workers are assigned is :

$Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_3=\frac{125+3\times30}{220}\\\\\\=0.98$

Hence, the cost of inventorying a single item is $0.98

d. To determine the most cost-effective job assignment, we calculate the cost of 4+ workers.

Take any number less than 235(say 234) as the inventory units:

$Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_4=\frac{125+4\times30}{234}\\\\\\=1.05$

From our calculations, it's clear that two workers per computer costs the least amount($0.93) per unit item. Hence, it is best to assign two workers per computer.

4 0

4 years ago

Add/subtract the following fractions. Express youre answer to it's Lowest term.

vodka [1.7K]

Answer:

$\frac{8}{8}$

$\frac{6}{5}$

<h2>hope it helps</h2>

have a good day

4 0

3 years ago

Help me pls, Due Today

horrorfan [7]

the same 3 angles and three sides

4 0

3 years ago

Read 2 more answers

Simplify fractions 7/21

matrenka [14]

Answer:

1/3

Step-by-step explanation:

7/21 = 1/3

This is because 21 & 7 are both multiples of 7. 7 / 7 = 1. 21 / 7 = 3.

That makes it 1/3.

Hope that helps! :)

5 0

3 years ago

Read 2 more answers