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2 years ago

Which expression is equivalent to (cd)5

Mathematics

1 answer:

gulaghasi [49]2 years ago

3 0

C^5d^5 is your answer

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2 years ago

A circle has a sector with area 33 pi and central angle of 11/6 pi radians. What is the area of the circle?

frosja888 [35]

Answer:

The area of the circle is $36\pi\ units^{2}$

Step-by-step explanation:

we know that

The area of a circle subtends a central angle of $2\pi$ radians

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2 years ago

Read 2 more answers

To graph the inequality y < -5x + 3, you would draw a solid line.<br> A. True<br> O B. False

OLga [1]

Answer:

A. True

explanation:

Inequalities that use ≤ or ≥ symbols are plotted with a solid line.

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2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%282%20%5Csqrt%7B3%20%2B%203%20%5Csqrt%7B2%29%20%7B%3F%7D%5E%7B2%7D%20%7D%20%7D%20" id="TexFor

AlladinOne [14]

Answer:

$\left(2\:\sqrt{3\:+\:3\:\sqrt{2}\:\:}\:\right)\:^2=4(3+3\sqrt{2})$

Step-by-step explanation:

Considering the radical expression

$\left(2\:\sqrt{3\:+\:3\:\sqrt{2}\:\:}\:\right)\:^2$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n$

$=2^2\left(\sqrt{3+3\sqrt{2}}\right)^2.....[A]$

Simplifying

$\left(\sqrt{3+3\sqrt{2}}\right)^2$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt{a}=a^{\frac{1}{2}}$

$=\left(\left(3+3\sqrt{2}\right)^{\frac{1}{2}}\right)^2$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc}$

$=\left(3+3\sqrt{2}\right)^{\frac{1}{2}\cdot \:2}$

$=3+3\sqrt{2}$ As $\frac{1}{2}\cdot \:2=1$

So, putting $3+3\sqrt{2}$ into Equation [A]

$=2^2\left(\sqrt{3+3\sqrt{2}}\right)^2.....[A]$

$\left(\sqrt{3+3\sqrt{2}}\right)^2=3+3\sqrt{2}$

So, Equation [A] becomes

$=2^{2}(3+3\sqrt{2})$

$=4(3+3\sqrt{2})$

Therefore,

$\left(2\:\sqrt{3\:+\:3\:\sqrt{2}\:\:}\:\right)\:^2=4(3+3\sqrt{2})$

Keywords: radical expression

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3 0

2 years ago