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Paha777 [63]
3 years ago
5

Linda purchase a prepaid phone card for $30. Long distance calls cost $.17 a minute using this card when do use her card. Linda

use her card only to make a long distance call if the remaining credit on her card is $22.52, how many minutes did her call last
Mathematics
1 answer:
balandron [24]3 years ago
7 0

Answer: her call lasted for 44 minutes

Step-by-step explanation:

Linda purchase a prepaid phone card for $30. This means that the credit on her card is $30.

Long distance calls cost $0.17 each. Linda use her card only to make a long distance call. Assuming she made a total of x minutes of long distance calls, the cost would be $0.17x. The amount remaining on her card will be

30 - 0.17x

if the remaining credit on her card is $22.52, the number of minutes,x that the call lasted will be

22.52 = 30 - 0.17x

0.17x = 30 - 22.52

0.17x = 7.48

x = 7.48/0.17 = 44

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A semicircle has an area of 76.97 squared km. Find it’s radius
shtirl [24]

Answer:

7 km

Step-by-step explanation:

Substitute:

The equation for area of a semi-circle is \frac{r^{2}\pi }{2}

A =  \frac{r^{2}\pi }{2}

76.97 =  \frac{r^{2}\pi }{2}

Multiply by 2 on both sides:

2(76.97) = ( \frac{r^{2}\pi }{2})2

153.94 = r^{2} \pi

Divide by pi on both sides:

153.94 = r^{2} \pi

/pi           /pi

49.03 ≈ r^{2}

Find the square root:

\sqrt{49.03} =\sqrt{r^{2} }

7 = r

7 0
3 years ago
Alma was shopping for a T-shirt. It was 15% off everything in the store. The regular price of the shirt was $16.00 it was on sal
sergiy2304 [10]

Answer:B.) No-40 cents too high


Step-by-step explanation:

To find the answer you need to fin the discount. So basically I did 16x15 and got 240. Than I divided that by 100. I got 2.40.Than I subtract 2.40 from 16 and got $13.60. Therefore it would be B

8 0
3 years ago
Winter is coming, so Sasha decides to buy new outdoor gear. She has a coupon good for 25% off. She buys a coat with an original
Gemiola [76]

Answer:

B. boots

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Choose all the quadratic pairs that are equivalent. 1 2 (x + 4)2 = 2 x2 + 8x + 15 = 0 (x − 5)2 = 1 x2 − 10x + 26 = 0 3(x − 1)2 +
Artemon [7]

Answer:

Only equation 1 and 2 are equal.

Step-by-step explanation:

2 (x + 4)2 = 2

2( x² + 8x+ 16) = 2               Applying the square formula

2x² + 16x+ 32 = 2

2x² + 16x+ 32 -2= 0

2x² + 16x+ 30 = 0

2( x² + 8x+ 15)= 0           Taking 2 as common

x2 + 8x + 15 = 0------------eq 1

x2 + 8x + 15 = 0-------------eq 2

(x − 5)2 = 1

x²-10x+25= 1             Applying the square formula

x²-10x+25- 1= 0

x²-10x+24= 0-------------eq 3

x2 − 10x + 26 = 0 -------------eq 4

3(x − 1)2 + 5 = 0

3( x²-2x+1)+5= 0               Applying the square formula

3x²-6x+3+5= 0

3x²-6x+ 8= 0-------------eq 5

3x2 − 6x + 8 =1

3x2 − 6x + 8 -1=0

3x2 − 6x + 7 =0-------------eq 6

3 0
3 years ago
Type the correct answer in each box. Use numerals instead of words.
Alex_Xolod [135]

Answer:


Step-by-step explanation:

Given that prices for a pair of shoes lie in the interval

[80,180] dollars.

Delivery fee 20% of price.  

i.e. delivery fee will be in the interval [4, 9]

(1/20th of price)

Total cost= price of shoedelivery cost

Hence f(c) = c+c/20 = 21c/20

The domain of this function would be c lying between 80 to 180

So domain =[80,180]

---------------------------------

Amount to be repaid = 42 dollars

Once he received this amount, the price would be

105+42 =147

But since price range is only [21*80/20, 21*180/20]

=[84, 189]

Since now Albert has 147 dollars, he can afford is

[80,147]




6 0
3 years ago
Read 2 more answers
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