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a_sh-v [17]
3 years ago
5

What is the following simplified product? Assume x greater-than-or-equal-to 0 2 StartRoot 8 x cubed EndRoot (3 StartRoot 10 x Su

perscript 4 Baseline EndRoot minus x StartRoot 5 x squared EndRoot) 24 x cubed StartRoot 5 x EndRoot minus 4 x squared StartRoot 10 x EndRoot 24 x cubed StartRoot 5 x EndRoot minus 4 x cubed StartRoot 10 x EndRoot 24 x cubed StartRoot 5 EndRoot minus 4 x cubed StartRoot 10 x EndRoot 24 x cubed StartRoot 5 x EndRoot + 4 x cubed StartRoot 10 x EndRoot
Mathematics
2 answers:
Lady bird [3.3K]3 years ago
5 0
Wow that’s a lot let me try to help
Sedbober [7]3 years ago
4 0

Answer:

The answer to this should be D on ed2020

Step-by-step explanation:

There's another post for this question where Cheerchar13 had answered.

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Answer:Y=3x(x-4)

Step-by-step explanation:

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valentinak56 [21]

Answer:

Step-by-step explanation: letter B is the right answer

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3 years ago
Read 2 more answers
There are 60 people waiting for a river raft ride. Each raft holds
andrey2020 [161]

If there are 60 people waiting for a river raft ride. Each raft holds

15 people. how Silvia's work can be used to find the number

of rafts needed is: total number of people/Number of people holded by  each raft.

<h3>Number of rafts needed</h3>

Using this formula

There are 136 people waiting for a river raft ride each raft holds 8 people.

Number of rafts needed=Number of people/Capacity of raft

Where:

Number of people = 60

Capacity of raft = 15 people

Let plug in the formula

Number of rafts needed=60/15

Number of rafts needed=4 rafts needed

Therefore if  raft holds 15 people. how Silvia's work can be used to find the number of rafts needed is: total number of people/<em>Number </em>of people holded by  each raft.

Learn more about Number of rafts needed here:brainly.com/question/8361379
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8 0
1 year ago
What are the real zeros of the function g(x) = x3 + 2x2 − x − 2?
Nat2105 [25]
Upon a slight rearrangement this problem gets a lot simpler to see.

x^3-x+2x^2-2=0  now factor 1st and 2nd pair of terms...

x(x^2-1)+2(x^2-1)=0

(x+2)(x^2-1)=0  now the second factor is a "difference of square" of the form:

(a^2-b^2) which always factors to (a+b)(a-b), in this case:

(x+2)(x+1)(x-1)=0

So g(x) has three real zero when x={-2, -1, 1}
4 0
3 years ago
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