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4 years ago

Macy estimated a product to be 800. The actual product is 768. Her estimate was an

Mathematics

1 answer:

Vladimir79 [104]4 years ago

6 0

Answer:

Overestimate

Step-by-step explanation:

it would be an underestimate if the number was lower than the actual number but since its larger than it is an overestimation.

hope this helps

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Find the volume of the composite figure. Explain your thought, explain how your arrived at your answer. SHOW YOUR WORK FOR FULL

Bond [772]

At the bottom of the composite figure we have half a sphere, of radius 10 in.

The volume of this hemisphere would be half the volume of the full sphere, or:

(1/2)(4/3)π(10 in)^3, or (2/3)π(1000 in^3), or (2000/3)π in^3.

On top is the cone of radius 10 and slant height 15 in. To find the volume of this cone-shaped solid, we'll need the height of the cone. This can be found using the Pyth. Thm. as follows:

15^2 = 10^2 + h^2, where h is the height of the cone.

225 = 100 + h^2, so that h= √125, or 5√5. The height of the cone is 5√5 in.

Then the volume of the cone is V = (1/3)(base)(height)

= (1/3)(π)(100 in^2)(5√5 in)

= 500√5/3(π) in^3

The total volume of the composite solid is then

(2000/3)(π in^3) + ( 500√5/3(π) ) in^3), or

(π/3)(4+√5) in^3. This comes out to 6.53 in^3, to the nearest hundredth.

7 0

3 years ago

-1 1/4 divided by 3/4

tamaranim1 [39]

-0.10416 /.going on forever

6 0

4 years ago

Read 2 more answers

For how many positive values of n are both n3 and 3n four-digit integers?

AVprozaik [17]

Answer:

No positive value of n

Step-by-step explanation:

we have to find out for how many positive values of n are both

$n^3 , 3^n$ our-digit integers

Let us consider first cube

we get 4digit lowest number is 1000 and it has cube root as 10.

Thus 10 is the least integer which satisfies four digits for cube.

The highest integer is 9999 and it has cube root as 21.54

or 21 the highest integer.

Considering 3^n we get,

3^10 is having 5 digits and also 3^21

Thus there is no positive value of n which satisfy that both n cube and 3 power n are four digits.

5 0

3 years ago

Show that the equation x^4/2021 − 2021x^2 − x − 3 = 0 has at least two real roots.

andreev551 [17]

The roots of an equation are simply the x-intercepts of the equation.

See below for the proof that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ has at least two real roots

The equation is given as: $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$

There are several ways to show that an equation has real roots, one of these ways is by using graphs.

See attachment for the graph of $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$

Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)

From the attached graph, we can see that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500

This means that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ has at least two real roots

Read more about roots of an equation at:

brainly.com/question/12912962

6 0

3 years ago

Can someone pls help me find this is important

Olenka [21]

Answer:

x=90° and y=35°

Step-by-step explanation:

to get x and y first you must find the middle angles based on the information you have so:

35+90+n=180° solve for n to get what the middle angles are (since they are vertical angles they are equal) so the middle angles are both 55 degrees

and then 180-x=that angle that is also on the line with x so we'll call it k

so k+55+y=180°

we can see that y equals 35* because I noticed that those are parallel lines on the outside of the triangle so 35* and y angles are congruent and y =35°

now 35+55+k=180°

solve for the angle next to x which we called k and it is 90°

so x=90° and y=35°

after all this math I realized that if they are parallel lines then we can just use that to figure it out so use the properties to find out that x=90° and y=35°

7 0

3 years ago

Read 2 more answers