Help pls i need this now

Mathematics

1 answer:

Yanka [14]2 years ago

7 0

Answer:

3.14

Step-by-step explanation:

Formula: $b= \sqrt{c^2-a^2}$

b= $\sqrt{2.1^2-1.4^2}$

b = $\sqrt{2.45}$

b = 1.57

To get x you need to double b which is

3.14

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valentinak56 [21]

Answer:

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Step-by-step explanation:

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1 year ago

Geri ran in a marathon race. It took her 3 hours and 28 minutes to run 26 miles. How many minutes did it take her to run 1 mile

nadya68 [22]

1 hour = 60 minutes, so 3 hours = 3 * 60 = 180 minutes.

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3 years ago

Read 2 more answers

Find the product.

4vir4ik [10]

Answer :

$6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3 {y}^{3} {z}+3 {y}^{2} {z}^{2}$

Step-by-step explanation :

To find the product of

$3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)$

First we expand the bracket ,

it implies that, we use the expression outside the bracket to multiply individual expressions inside the bracket.

Hence

$3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)$

$= 3 {y}^{2} z(2 {y}^{2} z) + 3 {y}^{2} z(4yz) - 3 {y}^{2} z(y )+3 {y}^{2} z( z)$

we now apply the law of indices

${a}^{m} \times {a}^{n} = {a}^{m+n}$

meaning, when you are multiplying two expressions with the same bases , repeat one of the bases and add the exponents.

Then, simplify to obtain

$= 6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3{y}^{3} {z}+3 {y}^{2} {z}^{2}$