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4 years ago

1/2x + 3/2x = 4x - 8

Mathematics

2 answers:

34kurt4 years ago

8 0

Answer:

x=4

Step-by-step explanation:

1/2x + 3/2x =4x-8 Combine like terms:

4/2x=4x-8

2x=4x-8

-2x -2x

0=2x-8

+8 +8

8=2x Divide:

4=x

Hope this helps:)

Citrus2011 [14]4 years ago

7 0

Answer:

x = 4

Step-by-step explanation:

1/2x + 3/2x = 4x - 8

4/2x = 4x - 8

2x = 4x - 8

4x - 2x = 8

2x = 8

x = 4

I think u can know this

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20 copies of the school yearbook together weigh 50 lb what is the weight of each book

dedylja [7]

Answer:

2.5 pounds per book

Step-by-step explanation:

Set up a proportion

20 copies / 50 pounds = 1 copy / x pounds

Cross multiply

20x = 50

Divide both sides by 20

x = 2.5 pounds

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6 0

2 years ago

Find range (R):27,12,15,21,24,9

worty [1.4K]

27-9= 18

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5 0

3 years ago

Read 2 more answers

Round 5,821,634 to the nearest hundredths thousand

kodGreya [7K]

5,822,000 would be the answer :)

6 0

3 years ago

The population of Guatemala in 2000 was 12.7 million.

kow [346]

Since the population of Guatemala follows an exponential growth, therefore the equation describing the population over time should be in the form:

p = p0 (1 + r)^t

where,

p = is the population at specified time t

p0 = is the initial population (measured starting year 2000) = 12.7 m

r = the growth rate

t = time in years

A. Calculating for the growth rate r when p = 30 and t = 20:

30 = 12.7 (1 + r)^20

1 + r = (30 / 12.7)^(1/20)

r = (30 / 12.7)^(1/20) – 1

r = 0.0440

So the equation is:

p = p0 (1.0440)^t

B. Calculating for the growth rate r when p = 30 and t = 125:

30 = 12.7 (1 + r)^125

1 + r = (30 / 12.7)^(1/125)

r = (30 / 12.7)^(1/125) – 1

r = 0.0069

So the equation is:

p = p0 (1.0069)^t

7 0

3 years ago

A study of 12,000 able-bodied make students at Syracuse University found that their times for the mile run were approximately No

REY [17]

Answer:

a) About 802 students ran the mile in less than 6 minutes

b) It took at least 8.06 minutes for the slowest 10% of the students to run the mile

c) 67.62% of students ran the mile in between 400 and 500 seconds.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 7.11, \sigma = 0.74$

a. About how many students ran the mile in less than 6 minutes?

Proportion who ran in less than 6 minutes is the pvalue of Z when X = 6. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6 - 7.11}{0.74}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

Out of 12000

0.0668*12000 = 801.6

About 802 students ran the mile in less than 6 minutes.

b. Approximately how long did it take the slowest 10% of the students to run the mile?

The slowest, the higher the time.

So this is the 100-10 = 90th percentile of times.

Which are times of X when Z = 1.28 and greater

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 7.11}{0.74}$

$X - 7.11 = 1.28*0.74$

$X = 8.06$

It took at least 8.06 minutes for the slowest 10% of the students to run the mile

c. Suppose that these mile run times are converted from minutes to seconds. Estimate the percent of students who ran the mile in between 400 and 500 seconds.

Each minute has 60 seconds. So

$\mu = 60*7.11 = 426.6, \sigma = 44.4$