The first thing to do in this case is to find the volume of the sphere. We have then: V = (4/3) * (pi) * (r ^ 3) V = (4/3) * (pi) * ((4) ^ 3) v = 268 in ^ 3 Then, the but of the sphere will be given by: W = (0.075) * (268) W = 20 Answer: the weight of the sphere, to the nearest pound is: A) 20
Given that: Area of triangle=23 cm² Dilation factor= 6 It means that the area of the dilated triangle is 6²=36 times of the original. Now area of dilated triangle, A'=36 x 23 A'= 828 cm²