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2 years ago

2x + 7 - 3x ⥶ 10 show work

Mathematics

1 answer:

gavmur [86]2 years ago

3 0

Answer:

x ⥶ -3

Step-by-step explanation:

2x - 7 -3x ⥶ 10

-x + 7 ⥶ 10

-x ⥶10 - 7

-x ⥶ 3

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The face of a clock has a circumference of 63 in. What is the area of the face of the clock?

ryzh [129]

Answer:

The area of the clock $= 315.41\ inch^{2}$

Step-by-step explanation:

We have been given the face of the clock that is $63\ in$

So that is also the circumference of the clock.

Since the clock is circular in shape.

So $2\pi(r)=63\ inch$

From here we will calculate the value of radius $(r)$ of the clock that is circular in shape.

Then $2\pi(r)=63\ inch =\frac{63}{2\pi} = 10.02\ in$

Now to find the area of the clock we will put this value of (r) in the equation of area of the circle.

Now $\pi (r)^{2}=\pi(10.02)^{2}=315.41\ in^{2}$

So the area of the face of the clock = $315.41\ in^{2}$

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2 years ago

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kobusy [5.1K]

$a(x+3) < 5x+15-x\\\\ax+3a < 5x+15-x\\\\ax+3a < 4x+15\ \ \ |-3a\\\\ax < 4x+15-3a\ \ \ \ |-4x\\\\ax-4x < 15-3a\\\\(a-4)x < 15-3a\\\\\text{The solution is all real numbers if}\ a-4=0\ \ \ |+4\\\\\boxed{a=4}\\\\\text{Check:}\\\\4(x+3) < 5x+15-x\\4x+12 < 4x+15\ \ \ \ |-4x\\12 < 15\ TRUE\to x\in\mathbb{R}$

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3 years ago

PLEASEE HELP FASTT Water flowed out of a tank at a steady rate. A total of 18 and one-half gallons flowed out of the tank in 4 a

Eddi Din [679]

Answer:

The answer would be D, 37/2 divided by 17/4

Explanation:

I did the test.

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2 years ago

Read 2 more answers

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ser-zykov [4K]

Answer:

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Step-by-step explanation:can you put more details?

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3 years ago

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Solve the system and give your answer as a coordinate point in the form (k, c) k+c=100 51k+11c=2500

Aleks [24]

Answer:

k = 35, c = 65

Step-by-step explanation:

Solve the following system:

{c + k = 100 | (equation 1)

{11 c + 51 k = 2500 | (equation 2)

Swap equation 1 with equation 2:

{11 c + 51 k = 2500 | (equation 1)

{c + k = 100 | (equation 2)

Subtract 1/11 × (equation 1) from equation 2:

{11 c + 51 k = 2500 | (equation 1)

{0 c - (40 k)/11 = -1400/11 | (equation 2)

Multiply equation 2 by -11/40:

{11 c + 51 k = 2500 | (equation 1)

{0 c+k = 35 | (equation 2)

Subtract 51 × (equation 2) from equation 1:

{11 c+0 k = 715 | (equation 1)

{0 c+k = 35 | (equation 2)

Divide equation 1 by 11:

{c+0 k = 65 | (equation 1)

{0 c+k = 35 | (equation 2)

Collect results:

Answer: {c = 65 , k = 35

5 0

3 years ago