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aleksklad [387]
4 years ago
10

Sweet t has 2 orange picks for every 5 green. if there are 21 picks in all how many picks are orange

Mathematics
2 answers:
Anestetic [448]4 years ago
8 0
Six oranges. Bdjsks nd
Vesna [10]4 years ago
6 0

For this case we have the following variables:

x: Quantity of orange picks

y: Quantity of green picks

According to the statement, we have the following proportion:

\frac{2}{5}=\frac{x}{y}, that is:

5x = 2y

If there are 21 picks, then:

x + y = 21

So, we have two equations with two unknowns:

5x = 2y ----> (1)

x + y = 21 ----> (2)

From (2):

x = 21-y

Substituting x in (1):

5 (21-y) = 2y\\105-5y = 2y\\105 = 7y\\

y = \frac{105}{7}\\y = 15

Substitutingy = 15 in (2) and clearing x, we have:

x + 15 = 21

x = 21-15

x = 6

So, there are 6 orange picks

Answer:

6 orange picks

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