Answer:
18.85, closest answer is A.
C=2πr=2·π·3≈18.84956
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The likelihood that an event would occur would be likely. This is because the event has already been set in place. You can’t assume the event is certain is the chance that it could be rescheduled or cancelled.
Denominator times whole number plus numerator, so:
66x2+3=135
The distribution is not a standard normal distribution.
We know that the variable (X) usually obeys and follows a standard normal distribution provided that the summation of (X) is zero and the variance of the random variable V(X) = 1.
Mathematically:
E(X) = 0 and V(X) = 1
Given that;
- the mean which follows a normal distribution (X) = 4.5338 g, and
- the standard deviation SD(X) = 0.1039 g
As such, the distribution is not a standard normal distribution.
Therefore, we can conclude that the distribution is not a standard normal distribution.
Learn more about standard normal distribution here:
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