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Margaret [11]
3 years ago
9

How do you change the mix number 66 2/3 into a regular number?

Mathematics
1 answer:
gavmur [86]3 years ago
6 0
Denominator times whole number plus numerator, so:
66x2+3=135
You might be interested in
Can someone help me plead
andrew-mc [135]

Answer:

a. 2^3

b. 3^4

c. 4^3 × 5^2

d. 9^4 × 7^2

Step-by-step explanation:

The following equations are given

a. 2 × 2× 2

b. 3 × 3 × 3 × 3

c. 4 × 4 × 4 × 5 × 5

d. 9 × 7 × 9 × 9 × 7 × 9

We need to find the index notation for the above equations

a. 2^3

b. 3^4

c. 4^3 × 5^2

d. 9^4 × 7^2

In this way it should be done

The same would be relevant

4 0
2 years ago
Brainly which is the distance between (-3,4) and (7,13)
Veseljchak [2.6K]

Answer:

Root 181

Step-by-step explanation:

         Using distance formula, we know that the answer will be the square root of 181. Unfortunately, this is not a perfect square, and it is prime, so that number will remain the same.

Distance Formula: \sqrt{(13-4)^{2} + (7+3})^2} = \sqrt{181}

Hope this helped!

5 0
3 years ago
Suppose that a box of 86 circuits is sent to a manufacturing plant. Of the 86 circuits shipped, 5 are defective. The plant manag
Triss [41]

Answer:

the probability that the shipment is accepted is 0.8865

Step-by-step explanation:

Given the data in the question;

N = 86,  n/d = 5 and n = 2

now, without replacement

the probability that the shipment is accepted will be;

probability that the shipment is accepted = probability that non is defectives

so p( non is defective ) = ( (86-5)/86) × ((86-5-1)/(86-1))            

p( non is defective ) =  ( 81 / 86) × (80/85)

p( non is defective ) =  0.8865

Therefore, the probability that the shipment is accepted is 0.8865

7 0
2 years ago
Neeed math hellppp!!!!
aleksklad [387]
Answer: A

Step by step: None
6 0
3 years ago
Read 2 more answers
When playing the roulette at a casino, you have exactly 1/35 chance of winning in each round if you play a single number. Your f
Vikentia [17]

Answer:

0.2275 = 22.75% probability that you actually won that round

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Fireworks going off

Event B: You won

Probability of fireworks going off.

100% of 1/35 = 0.0286(when you win)

10% of 34/35 = 0.9714(you lost). So

P(A) = 0.0286 + 0.1*0.9714 = 0.12574

Probability of you winning and fireworks going off:

100% of 1/35, so P(A \cap B) = 0.0286

If you failed to see the outcome of a round, but you see the fireworks going off, then what is the probability that you actually won that round?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0286}{0.12574} = 0.2275

0.2275 = 22.75% probability that you actually won that round

8 0
3 years ago
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