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scoray [572]
3 years ago
12

I really do not understand this unit can someone please help me.

Mathematics
1 answer:
san4es73 [151]3 years ago
6 0

Answer:

3) 441 m² (C)

Step-by-step explanation:

the square root of 29² - 20² is = 21 (side length of Q

21 is all of the side lengths since it's a square.

so multiply 21 by itself:

21x21= the area of q= 441 m²

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What is the slope of the line 4x – 2y = 5?
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Answer:

2

Step-by-step explanation:

2y=4x-5

divide each side by 2

y=2x-5/2

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3 years ago
A sequence consists of 20102010 terms. Each term after the first is 11 larger than the previous term. The sum of the 20102010 te
Nataliya [291]

You're considering a sequence of in which consecutive terms differ by 1, meaning

<em>a(n)</em> = <em>a</em> (<em>n</em> - 1) + 1

so <em>a(n)</em> is an arithmetic sequence. (I'm guessing 20102010 should actually be 2010, and 53075307 should be 5307, so 11 should probably be just 1.)

The sum of the first 2010 terms is 5307, or

\displaystyle\sum_{n=1}^{2010}a(n)=5307

Find the value of the first term in the sequence, <em>a</em>(1).

We can write <em>a(n)</em> in terms of <em>a</em>(1) by iterative substitution:

<em>a(n)</em> = <em>a</em>(<em>n</em> - 1) + 1

<em>a(n)</em> = (<em>a</em>(<em>n</em> - 2) + 1) + 1 = <em>a</em>(<em>n</em> - 2) + 2

<em>a(n)</em> = (<em>a</em>(<em>n</em> - 3) + 1) + 2 = <em>a</em>(<em>n</em> - 3) + 3

and so on, down to

<em>a(n)</em> = <em>a</em>(1) + <em>n</em> - 1

So the sum of the first 2010 terms is

\displaystyle\sum_{n=1}^{2010}a(n)=\sum_{n=1}^{2010}\left(a(1)+n-1\right)=(a(1)-1)\sum_{n=1}^{2010}1+\sum_{n=1}^{2010}n=5307

Recall that

\displaystyle\sum_{n=1}^N1=\underbrace{1+1+\cdots+1}_{N\text{ times}}=N

and

\displaystyle\sum_{n=1}^Nn=1+2+\cdots+N=\dfrac{N(N+1)}2

So we have

\displaystyle\sum_{n=1}^{2010}a(n)=2010(a(1)-1)+\frac{2010\cdot2011}2=5307

Solve for <em>a</em>(1) :

2010 (<em>a</em>(1) - 1) + 2,021,055 = 5307

2010 (<em>a</em>(1) - 1) = -2,015,748

<em>a</em>(1) - 1 = - 335,958/335

<em>a</em>(1) = - 335,623/335

Now, every second term, starting with <em>a</em>(1), differs by 2, so they form another arithmetic sequence <em>b(n)</em> given by

<em>b(n)</em> = <em>b</em>(<em>n</em> - 1) + 2

or, using the same method as before,

<em>b(n)</em> = <em>b</em>(1) + 2 (<em>n</em> - 1) = <em>a</em>(1) + 2<em>n</em> - 2

The sum of the 1005 terms in this sequence is

\displaystyle\sum_{n=1}^{1005}b(n)=(a(1)-2)\sum_{n=1}^{1005}1+2\sum_{n=1}^{1005}n

= (- 335,623/335 - 2)•1005 + 2•1005•1006/2

= 1146

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1/3 out of 15 is 5
And yeh
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Answer:

#2

Step-by-step explanation:

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