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3 years ago

Hey, can someone solve this for me? 5(x+1)= 4(x-1)+x

Mathematics

1 answer:

Travka [436]3 years ago

3 0

5(x+1)= 4(x-1)+x
5x + 5 = 4x - 4 + x
5x +5 = 5x -4
5 ≠ -4
x ∈ ∅

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PLEASE SOLVE THIS FOR ME ITS DUE TOMORROW Find an expression for the missing dimension.

denis-greek [22]

Answer:

The missing length is 2x+5

Step-by-step explanation:

Given equation of volume of cuboid is V= $2x^{3} +17x^{2} +46x+40$

Figure show that

Length of cuboid is ?

Width of cuboid is (x+4)

Height of cuboid is (x+2)

The volume of cuboid is given by

V=Length x Width x Height

Let Length be (bx+a)

The volume of cuboid will be

$V=(bx+a)(x+4)(x+2)$

$V=(bx+a)[x^{2}+4x+2x+8 ]$

$V=bx[x^{2}+6x+8]+a[x^{2}+6x+8]$

$V=[bx^{3}+6bx^{2}+8bx]+[ax^{2}+6ax+8a]$

$V=[bx^{3}+(6b+a)x^{2}+(8b+6a)x+8a]$

On comparing coefficient with given equation of volume

We get,

b=2 and 8a=40

Therefore, the value of a is 5 and b is 2

Thus, The missing length is bx+a=2x+5

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3 years ago