![\{0\} \not = \{\}](https://tex.z-dn.net/?f=%5C%7B0%5C%7D%20%5Cnot%20%3D%20%5C%7B%5C%7D)
because
![\{0\}](https://tex.z-dn.net/?f=%5C%7B0%5C%7D%20)
is a set with the element 0, so it's not the empty set, while
![\{\}](https://tex.z-dn.net/?f=%5C%7B%5C%7D)
is the empty set.
Answer:
![33 - 4x](https://tex.z-dn.net/?f=33%20-%204x)
Step-by-step explanation:
Given the term to be solved by explaining each step:
![13 - 4(x - 5)](https://tex.z-dn.net/?f=13%20-%204%28x%20-%205%29)
First of all, the bracket will be solved as per the BODMAS rule.
The bracket term is:
![4(x-5)](https://tex.z-dn.net/?f=4%28x-5%29)
Now, 4 will be multiplied with
and -5.
i.e.
![4(x-5)=(4\times x-4\times 5)\\\Rightarrow (4x-20)](https://tex.z-dn.net/?f=4%28x-5%29%3D%284%5Ctimes%20x-4%5Ctimes%205%29%5C%5C%5CRightarrow%20%284x-20%29)
Now, let us put the value back in the original expression.
![13 - 4(x - 5) = 13-(4x-20)](https://tex.z-dn.net/?f=13%20-%204%28x%20-%205%29%20%3D%2013-%284x-20%29)
Now, let us remove the bracket, negative sign will be multiplied with both i.e.
and -20
negative multiplied with negative makes positive term)
Now, 13 and 20 are like terms, they will be added.
the expression is equivalent to :
![\bold{33-4x}](https://tex.z-dn.net/?f=%5Cbold%7B33-4x%7D)
X^2 - 10x - 6 = 2x + 1
x^2 - 10x - 6 - 2x - 1 = 0
x^2 - 12x - 7 = 0
Answer
C. x^2 - 12x - 7 = 0