Question

Find the area of the shape shown below.

Answer 1

Answer: $42 units^{2}$

Explanation:

We can divide this figure in a rectangle with base $b=1 unit$ and height $h=12 units$; and a right triangle with base $B=5 units$ and height $H=12 units$.

Now, the total area $A$ of the figure will be the area of the rectangle $A_{rectangle}$ plus the area of the triangle $A_{triangle}$:

$A=A_{rectangle}+A_{triangle}$

Where:

$A_{rectangle}=(b)(h)=(1 unit)(12 units)=12 units^{2}$

$A_{triangle}=\frac{(B)(H)}{2}=\frac{(5 units)(12 units)}{2}=30 units^{2}$

Then:

$A=12 units^{2}+30 units^{2}$

$A=42 units^{2}$ This is the area of the figure