Someone who can do this help me please.

Tom throws a ball into the air. The ball travels on a parabolic path represented by the equation , where represents the height o

tigry1 [53]

Answer:

2.5 second

Step-by-step explanation:

The equation is missing in the question.

The equation is, $h=-8t^2+40t$ , where 'h' is the height and 't' is time measured in second.

Now we know to reach its maximum height, h in t seconds, the derivative of h with respect to time t is given by :

$\frac{dh}{dt} =0$

Now the differentiating the equation with respect to time t, we get

$\frac{dh}{dt}=\frac{d}{dt}(-8t^2+40t)$

$\frac{dh}{dt}=-16t+40$

For maximum height, $\frac{dh}{dt} =0$

So, $-16t+40=0$

$\Rightarrow 16t=40$

$\Rightarrow t=\frac{40}{16}$

$\Rightarrrow t = 2.5$

Therefore, the ball takes 2.5 seconds time to reach the maximum height.

7 0

3 years ago

Select the point that is a solution to the system if inequalities yx^2-6

labwork [276]

Answer:

The correct answer is A.

$A(0,-2)$

Step-by-step explanation:

Method 1

You just have to plot each point on the graph.

The one that falls within the solution region is the correct choice.

From the graph, $A(0,-2)$ falls within the solution region.

See graph

Method 2

If you substitute the points into the inequalities, the only point that will satisfy both inequalities simultaneously is A.

The first inequality is

$y\:$

If we substitute $A(0,-2)$ , we get;

$-2\:$

This statement is true.

The second inequality is

$y\:>\:x^2-6$

If we substitute $A(0,-2)$ , we get;

$-2\:>\:(0)^2-6$

This gives,

$-2\:>\:-6$

This statement is also true.

8 0

4 years ago

What is 80/400 as a decimal

elena55 [62]

80/400 as a decimal is 0.2

4 0

3 years ago

Write down the bearing of: (a) Henly from Dinder (b) Dinder from Weare (c) Weare from Dinder (d) Weare from Henly (e) Dinder fro

Neko [114]

The bearing of the individuals from each other are as indicated below;

S45°E
N25°E
S65°E
S15°E
N45°E
N75°E

<h3>What is bearing of Henley from Dinder?</h3>

It follows from the task content that the bearing of the individuals from each other are expected to be determined.

a) For Henley from Dinder; it follows from observation that Henley is; S45°E of Dinder's position.

b) For Dinder from Weare; it follows from observation that Dinder is; N25°E of Weare's position.

c) For Weare from Dinder; it follows from observation that Weare is; S65°E of Dinder's position.

d) For Weare from Henly; it follows from observation that Weare is; S15°E of Dinder's position.

e) For Dinder from Henly; it follows from observation that Dinder is; N45°E of Henly's position.

f) For Henly from Weare; it follows from observation that Henly is; N75°E of Weare's position.