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jarptica [38.1K]
3 years ago
15

6x^(2)(x^(3)y+2x-3yz)

Mathematics
1 answer:
horsena [70]3 years ago
5 0
The answer is 6x^5(y+2x-3yz)
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The lengths of the sides of a triangle are in the extended ratio 4 : 9 : 10. The perimeter of the triangle is 92 cm. What are th
Nookie1986 [14]
16, 36, 40

Set the problem up as 4x+9x+10x= 92

26x= 92

X= 4

Plug back in to get the lengths of the sides (shown above)
7 0
3 years ago
The grocery store charges $0.89 a pound for unsalted peanuts. If y represents the total cost and x represents the number of poun
Dmitry_Shevchenko [17]
Y = 0.89x <== ur equation
6 0
4 years ago
How do u do this.I need major help on it
Tpy6a [65]
Look for what 'y' is when t = 1 and t = 2. Go to the graph, look at 1 on the bottom axis and go up till you find the point, then go all the way to the left to see what the y-value is, in this case it should be 1200. If you do the same with t = 2, you will get 2400. So our two ordered pairs are:

(1, 1200), (2, 2400)

We can find the slope of these two points by plugging them into the slope formula:

\sf m=\dfrac{y_2-y_1}{x_2-x_1}

For points in the form of (x1, y1), (x2, y2). Plug in what we know:

\sf m=\dfrac{2400-1200}{2-1}

Subtract:

\sf m=\dfrac{1200}{1}

Divide:

\sf m=1200

This is the slope, so we can write the equation:

\boxed{\sf y=1200t}
4 0
3 years ago
Find the sum of the measures of the interior angles of the figure.
Ivahew [28]

Step-by-step explanation:

Given figure is of HEXAGON.

the sum of the measures of the interior angles of a hexagon

=  \frac{(6 - 2) \times 180 \degree}{6}  \times 6 \\  \\ =  {4 \times 30 \degree} \times 6  \\   \\ = 720 \degree

4 0
4 years ago
1. There are 78 sophomores at a school. Each is required to take at least one year of either chemistry or physics, but they may
SVETLANKA909090 [29]

We are given that there are a total of 78 students. If we set the following variables:

\begin{gathered} C=\text{students only in chemestry} \\ P=\text{students only in physics} \\ PC=\text{students in physics and chemistry} \end{gathered}

Then, the sum of all of these must be 78, that is:

C+P+PC=78

Since there are 15 in chemistry and physics and 47 in chemistry, we may replace that into the equation and we get:

47+P+15=78

Simplifying:

62+P=78

Now we solve for P by subtracting 62 on both sides:

\begin{gathered} 62-62+P=78-62 \\ P=16 \end{gathered}

Therefore, there are 16 students in physics

3 0
1 year ago
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