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3 years ago

Factor −6 out of −18a−30

Mathematics

2 answers:

fgiga [73]3 years ago

6 0

Remark

This is like using the distributive principle only you are going backwards. Instead of trying to remove brackets, you are trying to create them.

Solution

Since you want to take - 6 outside the brackets you should divide both terms by - 6

- 18a: - 18a/- 6 = 3a which is left inside the brackets.

-30: - 30/-6 = 5

- 6(3a + 5)

Answer

-6(3a + 5)

larisa86 [58]3 years ago

4 0

Answer: -6(3a + 5)

Step-by-step explanation:

Factoring -6 from 18a, you will be left with 3a because -6× 3a will give you 18a

Also factoring -6 from 30, you will be left with 5 because -6 ×5 = -30.

Therefore -18a -30

-6( 3a + 5)

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in one month darius spends 10 hours walking dogs. How many dogs walks does he do in one month ALSO this is dividing a whole numb

MA_775_DIABLO [31]

Step-by-step explanation:

let's assume one month is 30 days you would multiply 10 by 30.

$10 \times 30 = 300$

which would be 300 hours in 1 month

now if one month is 31 days you would simply multiply 10 by 31.

$10 \times 31 = 310$

which would be 310 hours

6 0

3 years ago

What is the minimum value of the function g(x) = x2 - 6x – 12? -21 3-21 3 3+21

balandron [24]

Answer:

- 21

Step-by-step explanation:

The minimum value occurs at the vertex of the function

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

To obtain this form use the method of completing the square

Given

f(x) = x² - 6x - 12

add/ subtract ( half the coefficient of the x- term)² to x² - 6x

f(x) = x² + 2(- 3)x + 9 - 9 - 12

= (x - 3)² - 21

with vertex = (3, - 21 )

The minimum is the value of k, that is minimum value = - 21

4 0

3 years ago

25)

Liula [17]

Answer:

A) w=3

Step-by-step explanation:

4 x 3 = 12

This is the work when you plug in the numbers in the varible w

6 0

3 years ago

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What is the square root of 25

anastassius [24]

Answer:

Step-by-step explanation:

5 square, which means 5 multiplied by 5 gives you 25

4 0

3 years ago

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Find the projection of u onto v URGENT HELP

padilas [110]

Given:

Two vectors are:

$u=\left$

$v=\left$

To find:

The projection of u onto v.

Solution:

Magnitude of a vector $v=\left$ is:

$|v|=\sqrt{a^2+b^2}$

Dot product of two vector $v_1=\left$ and $v_2=\left$ is:

$v_1\cdot v_2=a_1a_2+b_1b_2$

Formula for projection of u onto v is:

$Proj_vu=\dfrac{u\cdot v}{|v|^2}v$

$Proj_vu=\dfrac{\left \cdot \left }{(\sqrt{2^2+17^2)^2}}\left$

$Proj_vu=\dfrac{0\cdot 2+6\cdot 17}{4+289}\left$

$Proj_vu=\dfrac{0+102}{293}\left$

On further simplification, we get

$Proj_vu=\dfrac{102}{293}\left$

$Proj_vu=\left$

Therefore, the projection of u onto v is $Proj_vu=\left$ .

3 0

3 years ago