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dezoksy [38]
3 years ago
9

Solve y=x^2+23 for x

Mathematics
1 answer:
LenKa [72]3 years ago
7 0

For this case we must clear x from the given equation:

y = x ^ 2 + 23

We passed 23 subtracting the other side of equality:

y-23 = x ^ 2

By definition, a ^ 2 = bis written as a = +/-\sqrt{b}

So, we have:

x = + / -\sqrt{(y-23)

So, the solution of y = x ^ 2 + 23 for x is:

x = + / -\sqrt{(y-23)

Answer:

x = + / -\sqrt{(y-23)

x1=+\sqrt{(y-23)

x2=-\sqrt{(y-23)


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