They are both divisible by 3 so we divide both by 3 and get
3(5+7)
<em>p</em> … <em>q</em> … ¬<em>q</em> … <em>p</em> ∨ ¬<em>q</em> … (<em>p</em> ∨ ¬<em>q</em>) ⇒ <em>q</em>
T … T … F … T … T
T … F … T … T … F
F … T … F … F … T
F … F … T … T … F
Start with the first two columns, taking every possible pair of True/False for <em>p</em> and <em>q</em>.
¬<em>q</em> is just the negation of <em>q</em>, so True becomes False and False becomes True.
<em>p</em> ∨ <em>q</em> is the logical disjunction, or logical "or". It's True if either <em>p</em> or <em>q</em> is True, and False otherwise. So <em>p</em> ∨ ¬<em>q</em> is True only if either <em>p</em> or ¬<em>q</em> is True.
<em>p</em> ⇒ <em>q</em> is the logical implication. It's True only when both <em>p</em> and <em>q</em> are True, or when <em>p</em> is False. So (<em>p</em> ∨ ¬<em>q</em>) ⇒ <em>q</em> is True when both <em>p</em> ∨ ¬<em>q</em> and <em>q</em> are True, or when <em>p</em> ∨ ¬<em>q</em> is False.
To solve this problem you must apply the proccedure shown below:
1. Let's order the position of each runner shown in the table from greatest to least, to see which one is closer to zero:
-0.480 meters (Runner D).
= -0.56 meters (Runner E).
-1.05 meters (Runner C).
= -1.25 meters (Runner B).
-1.264 meters (Runner A).
= -1.625 meters (Runner F).
2. As you can see, the position of the runner that is closer to zero is:
-0.480 meters (Runner D)
3. Therefore the runner D finished in second place.
4. The runner B finished in fifth place.
The answer is: The runner D finished in second place and the runner B finished in fifth place.
Answer:
1/64
Step-by-step explanation:
First of all, you should know that:
direct variation:
y = c * x
Inverse variation:
y = c / x
where, c is any number that belongs to the real ones.
answer:
An equation that represents an inverse variation is
y = 4 / x