Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
That's 5 integers...
Logic tells me that a number divided by 5 should be equal to -3. -15/5 is in fact equal to -3.
Let's find 5 integers (two positive and three negative) when added up together equal -15.
-14, -3, -3, 2, 3.
[(-14)+(-3)+(-3)+2+3]/5 = (-15)/5 = -3
Mean = -3
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Now let's put these numbers in order, from lowest to highest - then pick out the middle value...
-14, -3, [-3], 2, 3
The median turns out to be -3.
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Let's look at the numbers once again...
-14, -3, -3, 2, 3
It turns out that -3 appears the most, therefore -3 is the mode too.
Step-by-step explanation:
A =1/2(a+b)h
hope it helps.
Answer:
Christianity
Step-by-step explanation:
I believe the answer is 35 degrees, or A.
