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Zielflug [23.3K]
3 years ago
8

Write an equation in slope intercept form for a line that passes through the origin with a slope of 3/2

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
4 0

Answer: y = (3/2)x

m = 3/2 is the slope

(x1,y1) = (0,0) is the point we want the line to go through, aka the origin

Use point slope form, plug in the given values, and convert to slope intercept form

y - y1 = m(x - x1) .... point slope form

y - 0 = (3/2)*(x - 0) .... substitution

y = (3/2)x .... final answer in slope intercept form

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Answer:

1/3 and 10/11, or 9/27 and 40/44

Step-by-step explanation:

Simplified 3/9  by 3.

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EastWind [94]

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Step-by-step explanation:

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4 years ago
Solve the following system of equations <br> Y= -2x – 3<br> 4y + x =16
Aleksandr-060686 [28]

Answer:

(-4,5)

*View attached graph*

Step-by-step explanation:

y = -2x - 3

4y + x = 16

4y + x = 16

4(-2x - 3) + x = 16

-8x - 12 + x = 16

-7x - 12 = 16

     +12   + 12

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/-7    /-7

x = -4

4y + x = 16

4y + (-4) = 16

4y - 4 = 16

   + 4   + 4

4y = 20

/4     /4

y = 5

(x,y) -> (-4,5)

Hope this helps!

6 0
3 years ago
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