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VikaD [51]
3 years ago
7

4/16 in the lowest terms

Mathematics
2 answers:
V125BC [204]3 years ago
7 0
1/4 .
4 divided by 4 is one
16 divided by 4 is 4
= 1/4
miskamm [114]3 years ago
6 0

Answer:

1/4

Step-by-step explanation:

The answer is 1/4 because 4 is the greatest common factor (GCF) of both numbers. So you divide both numbers by 4.

4 ÷ 4 = 1

16 ÷ 4 = 4

Therefore, the answer is 1/4.

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Which counter example shows that the following is false? Every perfect square has exactly three factors
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4 0
2 years ago
121degree 22' 36'' is like same as what?
Darina [25.2K]
22' is 22 minutes
there are 60 minutes in 1 degree, how many in 22? well, the short answer is you divide it by 60, or 22/60 0.37 or thereabouts, so that makes it 

121.037 degrees and 36''

36'' is 36 seconds, there are 60 seconds in 1 minute, so in short, just divide it by 60 as well, so 36/60 or 0.6 minutes

so, let us revise above some

121 degrees 22' and 36''

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or about .38

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The Dead Sea has an elevation of 1,360 feet below feet sea level. Which number below represents the Dead Sea ‘s elevation
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3 years ago
The circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm. (a) Use differentials to estimate the ma
andreev551 [17]

The maximum error in the calculated surface area is 24.19cm² and the relative error is 0.0132.

Given that the circumference of a sphere is 76cm and error is 0.5cm.

The formula of the surface area of a sphere is A=4πr².

Differentiate both sides with respect to r and get

dA÷dr=2×4πr

dA÷dr=8πr

dA=8πr×dr

The circumference of a sphere is C=2πr.

From above the find the value of r is

r=C÷(2π)

By using the error in circumference relation to error in radius by:

Differentiate both sides with respect to r as

dr÷dr=dC÷(2πdr)

1=dC÷(2πdr)

dr=dC÷(2π)

The maximum error in surface area is simplified as:

Substitute the value of dr in dA as

dA=8πr×(dC÷(2π))

Cancel π from both numerator and denominator and simplify it

dA=4rdC

Substitute the value of r=C÷(2π) in above and get

dA=4dC×(C÷2π)

dA=(2CdC)÷π

Here, C=76cm and dC=0.5cm.

Substitute this in above as

dA=(2×76×0.5)÷π

dA=76÷π

dA=24.19cm².

Find relative error as the relative error is between the value of the Area and the maximum error, therefore:

\begin{aligned}\frac{dA}{A}&=\frac{8\pi rdr}{4\pi r^2}\\ \frac{dA}{A}&=\frac{2dr}{r}\end

As above its found that r=C÷(2π) and r=dC÷(2π).

Substitute this in the above

\begin{aligned}\frac{dA}{A}&=\frac{\frac{2dC}{2\pi}}{\frac{C}{2\pi}}\\ &=\frac{2dC}{C}\\ &=\frac{2\times 0.5}{76}\\ &=0.0132\end

Hence, the maximum error in the calculated surface area with the circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm is 24.19cm² and the relative error is 0.0132.

Learn about relative error from here brainly.com/question/13106593

#SPJ4

3 0
2 years ago
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