Answer :
(a) Amount paid after using the coupon = $b - $5 = $(b-5)
(b) Amount paid = $23.45 - $5 = $(23.45-5) = $18.45
Amount paid = $54.83- $5 = $(54.83-5) = $49.83
Step-by-step explanation :
As we are given that:
Amount of coupon = $5
If amount of total bill = $b
Now we have to calculate the amount paid after using the coupon.
Amount paid after using the coupon = Total amount of bill - Amount of coupon
Amount paid after using the coupon = $b - $5 = $(b-5)
Now we have to calculate the amount paid if bill was $23.45.
Amount paid after using the coupon = Total amount of bill - Amount of coupon
Amount paid = $23.45 - $5 = $(23.45-5) = $18.45
Now we have to calculate the amount paid if bill was $54.83.
Amount paid after using the coupon = Total amount of bill - Amount of coupon
Amount paid = $54.83- $5 = $(54.83-5) = $49.83
The answer is B because the teacher is keeping count of the seeds that EACH student plants
You have to convert the percent into a decimal before you convert it into a fraction then you simplify the fraction.
Hope this helps! :)
Complete question :
Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.
What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.
Answer:
0.56 ; 0.60
Step-by-step explanation:
From The attached Venn diagram :
C = attend college ; J = has a job
P(C) = (35+45)/300 = 80/300 = 8/30
P(J) = (30+45)/300 = 75/300 = 0.25
P(C n J) = 45 /300 = 0.15
1.)
P(J | C) = P(C n J) / P(C)
P(J | C) = 0.15 / (8/30)
P(J | C) = 0.5625 = 0.56
2.)
P(C | J) = P(C n J) / P(J)
P(C | J) = 0.15 / (0.25)
P(C | J) = 0.6 = 0.60