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ExtremeBDS [4]
3 years ago
12

Prove the identity

Mathematics
1 answer:
Troyanec [42]3 years ago
3 0

Answer:

Proved

Step-by-step explanation:

The options are not given. So, I will solve from scratch

Given

\frac{secx-1}{tan x}= \frac{tanx}{secx+1}

Required

Prove

Multiply the right-hand side by \frac{secx + 1}{secx + 1}

\frac{secx-1}{tan x} * \frac{secx + 1}{secx + 1}= \frac{tanx}{secx+1}

Apply difference of two squares on the numerator

\frac{sec^2 x - 1}{(tanx)(secx + 1)} =\frac{tanx}{secx+1}

In trigonometry:

tan^2x = sec^2x - 1

So, we have:

\frac{tan^2 x}{(tanx)(secx + 1)} =\frac{tanx}{secx+1}

\frac{tan x * tan x}{(tanx)(secx + 1)} =\frac{tanx}{secx+1}

tan x cancels out

\frac{tan x}{secx + 1} =\frac{tanx}{secx+1}

<em>Proved</em>

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Answer :

(a) Amount paid after using the coupon = $b - $5 = $(b-5)

(b) Amount paid = $23.45 - $5 = $(23.45-5) = $18.45

Amount paid = $54.83- $5 = $(54.83-5) = $49.83

Step-by-step explanation :

As we are given that:

Amount of coupon = $5

If amount of total bill = $b

Now we have to calculate the amount paid after using the coupon.

Amount paid after using the coupon = Total amount of bill - Amount of coupon

Amount paid after using the coupon = $b - $5 = $(b-5)

Now we have to calculate the amount paid if bill was $23.45.

Amount paid after using the coupon = Total amount of bill - Amount of coupon

Amount paid = $23.45 - $5 = $(23.45-5) = $18.45

Now we have to calculate the amount paid if bill was $54.83.

Amount paid after using the coupon = Total amount of bill - Amount of coupon

Amount paid = $54.83- $5 = $(54.83-5) = $49.83

6 0
3 years ago
Factor completely x_ - 36. (1 point)<br> (x + 6)(x - 6)<br> (X+6)(x+6)<br> (X-6)(x - 6)<br> Prime
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Answer:

Step-by-step explanation:

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3 years ago
What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as
Andrej [43]

Complete question :

Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.

What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.

Answer:

0.56 ; 0.60

Step-by-step explanation:

From The attached Venn diagram :

C = attend college ; J = has a job

P(C) = (35+45)/300 = 80/300 = 8/30

P(J) = (30+45)/300 = 75/300 = 0.25

P(C n J) = 45 /300 = 0.15

1.)

P(J | C) = P(C n J) / P(C)

P(J | C) = 0.15 / (8/30)

P(J | C) = 0.5625 = 0.56

2.)

P(C | J) = P(C n J) / P(J)

P(C | J) = 0.15 / (0.25)

P(C | J) = 0.6 = 0.60

5 0
3 years ago
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