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Dafna1 [17]
4 years ago
10

what ordered pair is 2 spaces to the left and 4 spaces down from the point graphed on the coordinate plane?

Mathematics
1 answer:
kykrilka [37]4 years ago
8 0
C. (-1, -2) would be your answer
That transformation is just a translation (x-2, y-4) from point (1,2)
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Which graph represents the equation x=-2
mixas84 [53]

graph c

because the graph x = -2 is a vertical line at -2 on the x axis

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3 years ago
25A2B is a 5-digit number. If the number is divisible by 5 and 9, find all the possible values of A and B. Explain also.
3241004551 [841]

Answer:

25020, 25920, 25425

Step-by-step explanation:

To find if our number is divisible by 5 the number must end with 0 or 5, divisibility by 9 is if sum of all numbers in number is divisible by 9,

We know B must end with 0 or 5

1. Case 25A20 sum of that number is 9 so if we pick 0 as A we have first number because 9/9=1

We can put A as 9 because 18/9=2

2. Case B = 0, sum is 14 so we need pick A as 4 to get 18.

7 0
3 years ago
WILL GIVE BRAINLIEST TO FIRST TO RESPOND Shape 1 is similar to shape 2
sdas [7]

Answer:

both are quadrilaterals

Step-by-step explanation:

6 0
3 years ago
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The measure of ∠FHJ is 60°. The measure of ∠FGH is 28°.<br><br><br><br> What is the measure of ∠HFG?
Licemer1 [7]
The answer is 32 b<span>ecause I know the angle of FHG is 120 and the angle of FGH is 28. so, 180 - 148 </span><span>
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4 0
3 years ago
Use the Rational Zero Theorem to list all possible rational zeros for the given function. f(x) = 10x^5 + 8x^4 - 15x^3 +2x^2 - 2
vagabundo [1.1K]

Given:

The function is:

f(x)=10x^5+8x^4-15x^3+2x^2-2

To find:

All the possible rational zeros for the given function by using the Rational Zero Theorem.

Solution:

According to the rational root theorem, all the rational roots are of the form \dfrac{p}{q},q\neq 0, where p is a factor of constant term and q is a factor of leading coefficient.

We have,

f(x)=10x^5+8x^4-15x^3+2x^2-2

Here,

Constant term = -2

Leading coefficient = 10

Factors of -2 are ±1, ±2.

Factors of 10 are ±1, ±2, ±5, ±10.

Using the rational root theorem, all the possible rational roots are:

x=\pm 1,\pm 2,\pm \dfrac{1}{2}, \pm \dfrac{1}{5},\pm \dfrac{2}{5},\pm \dfrac{1}{10}.

Therefore, all the possible rational roots of the given function are \pm 1,\pm 2,\pm \dfrac{1}{2}, \pm \dfrac{1}{5},\pm \dfrac{2}{5},\pm \dfrac{1}{10}.

5 0
3 years ago
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