Question

25A2B is a 5-digit number. If the number is divisible by 5 and 9, find all the possible values of A and B. Explain also.

Answer 1

Answer:

25020, 25920, 25425

Step-by-step explanation:

To find if our number is divisible by 5 the number must end with 0 or 5, divisibility by 9 is if sum of all numbers in number is divisible by 9,

We know B must end with 0 or 5

1. Case 25A20 sum of that number is 9 so if we pick 0 as A we have first number because 9/9=1

We can put A as 9 because 18/9=2

2. Case B = 0, sum is 14 so we need pick A as 4 to get 18.