Question

The sum of 4 consecutive integers is 126 what is the second highest integer

Answer 1

Answer:

32

Step-by-step explanation:

First, we must create an equation. If the integers are consecutive, it means that one comes right after the other (the difference is one). Here is the equation that will allow us to solve this problem:   (x) + (x + 1) + (x + 2) + (x + 3) = 126. Note that, although I have added parenthesis, these are just to separate each of the four integers we have not solved for yet. In your work, they will not make a difference in the answer!

Second, let's solve, beginning by combining like terms! There are four x's and 6 "regular" numbers (numbers without coefficients, in this case found by taking 1+2+3). This can be written out like so: 4x + 6 = 126.

Next, we must subtract the 6 from the left side and the right side in order to keep them equal. This gives us: 4x = 120.

Finally, let's divide both sides by four to find x!!! 120/4 =  30, meaning that: x = 30! For the last step, we must add 1, 2, and 3 to 30 to find all of the numbers. 30 + 1 = 31; 30 + 2 = 32, and 30 + 3 = 33! This gives us all four of our numbers: 30, 31, 32, and 33. The second highest of these is 32, which is our answer!

If you have any additional questions, please just comment below my answer and I'd be happy to help!

Answer 2

Second highest integer will have value of $n+2$.

$n+(n+1)+(n+2)+(n+3)=126 \\4n+6=126 \\n=30$

So the value of the second highest of the consecutive integers is 32.

Hope this helps.